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3 years ago

Which decimals are less than –2.08?

Mathematics

1 answer:

AVprozaik [17]3 years ago

4 0

Would it be C? im not too sure but thats my guess =)

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Select the correct answer. x Probability 0 0.2 1 0.1 2 0.4 3 0.2 4 0.1 The probability distribution of x, a discrete random vari

Alex_Xolod [135]

Answer: The option B. 1.9 is correct

Explanation:

We are given the below information:

x Probability P(x)

0 0.2

1 0.1

2 0.4

3 0.2

4 0.1

The expected value of x is given below:

$E(x)=\sum x P(x)$

$=(0 \times 0.2)+(1 \times 0.1)+(2 \times 0.4)+(3 \times 0.2)+(4 \times 0.1)$

$=0+0.1+0.8+0.6+0.4$

$=1.9$

Therefore, the expected value of x is 1.9

7 0

3 years ago

2. Ahmed has ¢15.25 and spent $7.50 at the<br> Total Shop. How much money does he have<br> left?

slava [35]

Answer:

D)¢ 8.75

Step-by-step explanation:

that is my answer please

5 0

2 years ago

Resolute academy algebra 1

Goryan [66]

Answer:

Step-by-step explanation:

We can see in the expression that there are 2 x² blocks, 4 -x blocks, and 3 -1 blocks. Therefore, we can write this as

2 * x² + 4 * (-x) + 3 * (-1) = 2x²-4x-3

Comparing this with each answer, we have

A: x²-2x-4 + x² + 2x-1 = 2x²-5. This is not correct

B: 3x²-7x+1-(x²-3x+4) = 3x²-7x+1 -x²+3x-4 = 2x²-4x-3. This seems correct but we can check the other answers to be sure

C: (2x+1)(x-3) = 2x²-6x+x-3 = 2x²-5x-3. This is incorrect

D: $\frac{8x^{12} - 16x^7 - 12x^6}{4x^6} = 2x^6 - 4x - 3$ . This is incorrect

3 0

3 years ago

A box weighs 90 grams.<br>Write down, in terms of b, the weight of b boxes.

Drupady [299]

Answer:

Let B = the weight of box B

Let 2B = the weight of box A

Let 2B + 30 = the weight of box C

B + 2B + 2B + 30 = 640

5B = 610

B = 122 pounds, weight of box B

2B = 2(122) = 244 pounds, weight of box A

2B + 30 = 2(122) + 30 = 274 pounds, weight of box C

hope this helps

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7 0

3 years ago

The fifth grade students 15/20 went to the book fair of the students who went to the book fair 12/16 bought at least one book wh

grin007 [14]

Answer:

$\frac{9}{16}$

Step-by-step explanation:

Out of a total of 1, $\frac{15}{20}$ went to the fair and $\frac{12}{16}$ OF THOSE, bought atleast one book.

To find the fraction of students who bought at least one book, we will multiply both the fractions. That is the answer. Shown below:

$\frac{15}{20}*\frac{12}{16}\\=\frac{3}{4}*\frac{3}{4}\\=\frac{9}{16}$

Answer is $\frac{9}{16}$

8 0

3 years ago