Complete Question
Suppose there was a cancer diagnostic test was 95% accurate both on those that do and 90% on those do not have the disease. If 0.4% of the population have cancer, compute the probability that a particular individual has cancer, given that the test indicates he or she has cancer.
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability that the test was accurate given that the person has cancer is
The probability that the test was accurate given that the person do not have cancer is
The probability that a person has cancer is
Generally the probability that a person do not have cancer is
=> 
=> 
Generally the probability that a particular individual has cancer, given that the test indicates he or she has cancer is according to Bayes's theorem evaluated as
=> 
=>
Take -20 - 8 = -28 C. the temperature at midnight
The average rate of change is -5 per month
<h3>How to determine the average rate of change?</h3>
The interval is given as:
July to December
From the graph, we have:
July = 110
December = 30
The average rate of a function over the interval (a, b) is calculated as:
Rate = [f(b) - f(a)]/[b - a]
So, we have:
Rate = (30 - 110)/(December- July)
This gives
Rate = (30 - 110)/(12 - 7)
Evaluate
Rate = -16
Hence, the average rate of change is -5 per month
Read more about average rate of change at:
brainly.com/question/23715190
#SPJ1
Answer: 80%
80,000 = 100%
20,000 = 20%
100% - 20% = 80%
Always convert the main number into 100 and follow through with the other numbers
We have the following expression:
(x- (5/2)) ^ 2 = (13/4)
Let's rewrite the given expression:
x ^ 2 - 5x + 25/4 = (13/4)
x ^ 2 - 5x + 25/4 - 13/4 = 0
x ^ 2 - 5x + 12/4 = 0
x ^ 2 - 5x + 3 = 0
Answer:
the original equation given to Sam could have been:
x ^ 2 - 5x + 3 = 0
