In ΔKLM, the measure of ∠M=90°, KM = 40, LK = 41, and ML = 9. What ratio represents the tangent of ∠K?
1 answer:
Answer:
The ratio representing the tangent of ∠K is 40 : 9.
Step-by-step explanation:
Consider the right-angles triangle KLM below.
The angle M is 90°.
KM = perpendicular (<em>p</em>) = 40
ML = base (<em>b</em>) = 9
LK = hypotenuse (<em>h</em>) = 41
The tangent of an angle is the ratio of the perpendicular length to the length of the base.
Compute the tangent of ∠K as follows:
Thus, the ratio representing the tangent of ∠K is 40 : 9.
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<span>x to the one twelfth power = </span>
<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>
<span>
Since </span>
then
Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4
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x times x to the second times x to the fifth = x * x² * x⁵
<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
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