Why now :cccccccccccccccccc
Step-by-step explanation:
For quadratic equation ax^2 + bx + c = 0 to have two distinct real roots,
b^2 - 4ac must be positive.
b^2 - 4ac > 0
(k - 3)^2 - 4(3 - 2k) > 0
k^2 - 6k + 9 - 12 + 8k > 0
k^2 + 2k - 3 > 0
Step-by-step explanation:
since packages are similarsimilar packages. The ratio of the volumes is 8:125. Determine the dimensions of the bigger package. The dimensions of the smaller package are... Height= 45cm, Length= 80cm, and Width= 25cm.
Length of bigger package = <em><u>8</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>c</u></em><em><u>m</u></em>
Width of bigger package =<em><u>2</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>3</u></em><em><u>9</u></em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>2</u></em><em><u>5</u></em><em><u>c</u></em><em><u>m</u></em>
Height of bigger package =<em><u>4</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>7</u></em><em><u>0</u></em><em><u>3</u></em><em><u>.</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>cm</u></em>
Answered: listen linda, braianly is broken anywya so just quit
Step-brother-by-Step-brother explanation:
Answer:
a) SPAZ is equilateral.
b) Diagonals SA and PZ are perpendicular to each other.
c) Diagonals SA and PZ bisect each other.
Step-by-step explanation:
At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.
a) If figure is equilateral, then SP = PA = AZ = ZS:
![SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}](https://tex.z-dn.net/?f=SP%20%3D%20%5Csqrt%7B%5B4-%28-4%29%5D%5E%7B2%7D%2B%5B%28-2%29-%28-4%29%5D%5E%7B2%7D%7D)

![PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}](https://tex.z-dn.net/?f=PA%20%3D%20%5Csqrt%7B%286-4%29%5E%7B2%7D%2B%5B6-%28-2%29%5D%5E%7B2%7D%7D)



![ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}](https://tex.z-dn.net/?f=ZS%20%3D%20%5Csqrt%7B%5B-4-%28-2%29%5D%5E%7B2%7D%2B%28-4-4%29%5E%7B2%7D%7D)

Therefore, SPAZ is equilateral.
b) We use the slope formula to determine the inclination of diagonals SA and PZ:




Since
, diagonals SA and PZ are perpendicular to each other.
c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:








Then, the diagonals SA and PZ bisect each other.