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3 years ago

7

-6x - 24 = 10 -2x - 2 Please help & show you get to the answer

2 answers:

julia-pushkina [17]3 years ago

6 0

Combine like terms:
-4x=32
divide by -4 to get x by itself
x=-8

Zanzabum3 years ago

3 0

Solve for x by simplifying both sides of the equation, the isolating the variable. x=-8

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HELP PLEASE!!!! OFFERING POINTS!

Aloiza [94]

Answer:

find the missing numbers

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Identify which of the following is not equivalent to 2 3/4.

mezya [45]

The figure that is not equivalent to 2¾ is 2¼ × 2½. That is option B.

<h3>Simplification of equivalent fractions</h3>

Simplification is a process that is used to make a fraction appear in its simplest forms.

The fraction given is = 2¾

The simplification of the fraction= 2^3/4 = 2

But simplification of 2¼ × 2½ is equal to;

2¼= 0.5

2½= 1

Therefore 2¾ is not equivalent to 2¼ × 2½ when simplified.

Learn more about fraction here:

brainly.com/question/78672

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6 0

2 years ago

Explain how 49. 567 is done in fraction form

pav-90 [236]

<span>= 49567/1000

</span>rite the decimal number as a fraction
(over 1)
49.567 = 49.567 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's

Numerator (N)
N = 49.567 × 10 × 10 × 10 = 49567
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000

N / D = 49567 / 1000

Simplifying our fraction

<span>= 49567/1000</span>

7 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

What base-ten number is 14 tens and 4 ones?¿

MrMuchimi

Answer:144

Step-by-step explanation:

7 0

4 years ago