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lisabon 2012 [21]
3 years ago
6

3 mangoes and 2 oranges have a mass of 200gm and 4 mangoes and 4 oranges have a mass of 300gm. Find out the mass of each fruit.

Mathematics
2 answers:
LenKa [72]3 years ago
7 0
So, make two equations.

3m+2o=200
4m+4o=300

If you multiply the first equation by 2, you get 6m+4o=400.

You can take away the second equation from this so that you have
2m=100.

Therefore, m=50.

Substitute this into one of the first equations, I'm going to use the first one.

3(50)+2o=200
150+2o=200
2o=50
o=25

And finally, check by substituting into the second equation.

4(50)+4(25)=300
200+100=300

Hope this helps :)

mestny [16]3 years ago
5 0
Start by defining your variables
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm

now, write the question as a system of equations

3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300

now you have a system of equations
3x+2y =200
4x+4y =300

solve for x and y
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We have assumed that n(n+1)(n+2) is divisble by 6.

We now only need to prove that 3(n+1)(n+2) is divisible by 6.

If 3(n+1)(n+2) is divisible by 6, then (n+1)(n+2) must be divisible by 2.

The "cool" part about this proof.

Since n is a natural number greater than 1 we can say the following:

If n is an odd number, then n+1 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.

If n is an even number" then n+2 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.

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