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NeX [460]
3 years ago
15

Choose the ratio you would use to convert 88 pounds to ounces remember that there are 16 ounces in 1 pound

Mathematics
2 answers:
djyliett [7]3 years ago
8 0

Answer:

The ratio that we use to convert 88 pound to ounces is:

B. 16 ounces/1 pound

Step-by-step explanation:

There are 16 ounces in 1 pound

i.e. 1 pound=16 ounces

     88 pound=88 pound × 16 ounces/1 pound

Hence, the ratio that we used to convert 88 pound to ounces is:

B. 16 ounces/1 pound

evablogger [386]3 years ago
4 0
Your answer would be B. 16 ounces/1 pound
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The  best approximation for the solution to this system of equations is (-2.2,-3)

Option C is correct.

Step-by-step explanation:

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Log16^*+log4^*+log2^*=7​
ale4655 [162]

Answer:

x = 16

Step-by-step explanation:

Given

log_{16}(x) + log_4(x) + log_2(x) = 7

Required

Solve for x

log_{16}(x) + log_4(x) + log_2(x) = 7

Change base of 16 and base of 4 to base 2

\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7

Express 16 and 4 as 2^4 and 2^2 respectively

\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7

The above can be rewritten as:

\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7

log_22 = 1

So, we have:

\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7

\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7

Multiply through by 4

4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4

log_2(x) + 2}log_2(x) + 4log_2(x) = 28

7log_2(x) = 28

Divide through by 7

\frac{7log_2(x)}{7} = \frac{28}{7}

log_2(x) = 4

Apply the following law of logarithm:

<em>If </em>log_ab = c<em> </em><em>Then </em>b = a^c<em></em>

So, we have:

x = 2^4

x = 16

6 0
3 years ago
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