We are given that the passenger's jet is flying at a speed of 185 miles per hour, with a direction of 36 degrees, and the wind speed being 47 mph with a direction of 120 degrees. From this, you could create a diagram is shown in the attachment.

[ 185 cos 36, 185 sin 36 ]

+ [ 47 cos 120, 47 sin 120 ]

_______________________

[ 185 cos 36 + 47 cos 120, 185 sin 36 + 47 sin 120 ]

√( 4263 + 33988 )^2

= ( About ) √38251 = 195.57 mph

Solution = 195.6 mph, 069°

4 0

4 years ago

The scale on a map is 1 :50000.

mestny [16]

Answer:

The actual area of the field in square kilometers is $30000000 km^2$

Step-by-step explanation:

Scale : 1 cm = 50000 km

Area of field on map = $1.2 cm^2$

Now , 1 cm = 5000 km

$1 cm^2 = (5000 km)^2$

We are supposed to find the actual area of the field in square kilometers.

So, the actual area of the field in sq. km = $1.2 \times (5000)^2$

Actual area of the field in sq. km $=30000000 km^2$

Hence the actual area of the field in square kilometers is $30000000 km^2$

6 0

3 years ago

Simplify (2m^2*n^-1)/(18m^3*n^-5)

Simplify (2m^2n^-1)/(18m^3n^-5)