The points scored by a basketball team in its last 6 gamesare shown. Use these data for 7 and 8.Points Scored73 77 85 84 37 1157
. Find the mean score and the median score.MeanMedians. Which measure better describes the typical number of points scored?Explain.
1 answer:
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Solution:
There is no (zero) complex zeros for the given polynomial.
Explanation:
We apply Descartes' rule of sign to identify the number of complex roots.
The given polynomial is
Let us see the number of sign changes in f(x)
+,-,+
There are 2 sign changes in f(x). One from plus to minus and second from plus to minus. Hence, there 2 or 0 positive roots.
Now, let us see the number of sign changes in f(-x)
-,-,+
There are only one sign change. Hence, there will be 1 negative roots.
The degree of the polynomial is 3. Hence, there will be exactly 3 zeros.
Therefore, the possible numbers of zeros are
2 positive, 1 negative and 0 complex
0 positive, 1 negative and 2 complex.
Hence, possible number of complex zeros are 0 and 2.
Now, we graph the function in xy plane and see that the graph cuts the x axis at three points. It means all the zeros are real , which is the case of first possibility (2 positive, 1 negative and 0 complex).
Hence, the number of complex zeros for the given polynomial is zero.
Answer:
» substitute y in eqn(a) with y in eqn(b)
» Find y in eqn(b)
Answer:
λN N(0) = 6
N(t) = N₀e^(λt)
Applying the inital value condition
N(t) = 6e^(λt)
Step-by-step explanation:
Summarizing the information briefly and stating the variables in the problem.
t = time elapsed during the decay
N(t) = the amount of the radioactive substance remaining after time t
λ= The constant of proportionality is called the decay constant or decay rate
Given the initial conditions
N(0) = N₀ = 6
The rate at which a quantity of a radioactive substance decays () is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :
λN
N(t) = N₀e^(λt) ......equ 1
substituting the value of N₀ = 6 into equation 1
N(t) = 6e^(λt)