Hooking ring is thrown. what is the probability of a hooking an even number?

One month Kaitlin rented 2 movies and 5 video games for total of $34. The next month she rented 8 movies and 3 video games for t

Tamiku [17]

Answer:

A movie is $4.50 and a video game is $5

Step-by-step explanation:

Create a system of equations where m is the cost of each movie and v is the cost of each video game:

2m + 5v = 34

8m + 3v = 51

Solve by elimination by multiplying the top equation by -4:

-8m - 20v = -136

8m + 3v = 51

Add these together and solve for v:

-17v = -85

v = 5

So, a video game is $5. Plug in 5 as v into one of the equations, and solve for m:

2m + 5v = 34

2m + 5(5) = 34

2m + 25 = 34

2m = 9

m = 4.5

A movie is $4.50 and a video game is $5

4 0

4 years ago

A manager at a company that manufactures cell phones has noticed that the number of faulty cell phones in a production run of ce

ExtremeBDS [4]

Answer:

a) Poisson probability distribution

b) The probability of no faulty cell phones will be produced tomorrow is 0.1653

c) The probability of 3 or more faulty cell phones were produced in today's run is 0.2694

Step-by-step explanation:

Poisson distribution is used for independent events which occur at a constant rate within a given interval of time

The Poisson probability distribution formula is P(x; μ) = (e^-μ) (μ^x) / x! where

x is the actual number of successes that result from the experiment

e is approximately equal to 2.71828

μ is the mean of the distribution

The number of faulty cell phones in a production run of cell phones is usually small and that the quality of one day's run seems to have no bearing on the next day

That means the probability of finding faulty phones in first day not depend on finding another days

Then the model might you use to model the number of faulty cell phones produced in one day is Poisson probability distribution

a) Poisson probability distribution

∵ The mean number of faulty cell phones is 1.8 per day

∴ μ = 1.8

∵ There is no faulty cell phones will be produced tomorrow

∴ x = 0

- Use the formula above to find the probability

∵ P(0 ; 1.8) = (e^-1.8) (1.8^0) / 0!

- Remember 1.8^0 = 1 and 0! = 1

∴ P(0 ; 1.8) = (e^-1.8)(1)/(1)

∴ P(0 ; 1.8) = 0.1653

b) The probability of no faulty cell phones will be produced tomorrow is 0.1653

∵ The mean number of faulty cell phones is 1.8 per day

∴ μ = 1.8

∵ There is 3 or more faulty cell phones were produced in today's run

∴ x ≥ 3

∵ P(x ≥ 3) = 1 - P(x = 0) - P(x = 1) - P(x = 2)

- Let us find P(1 ; 1.8) and P(2 ; 1.8)

∵ P(1 ; 1.8) = (e^-1.8) (1.8^1) / 1!

∵ 1.8^1 = 1.8

∵ 1! = 1

∴ P(1 ; 1.8) = (e^-1.8)(1.8)/(1)

∴ P(1 ; 1.8) = 0.2975

∵ P(2 ; 1.8) = (e^-1.8) (1.8^2) / 2!

∵ 1.8^2 = 3.24

∵ 2! = 2

∴ P(2 ; 1.8) = (e^-1.8)(3.24)/(2)

∴ P(2 ; 1.8) = 0.2678

Substitute them in the rule above

∵ P(x ≥ 3 ; 1.8) = 1 - 0.1653 - 0.2975 - 0.2678

∴ P(x ≥ 3 ; 1.8) = 0.2694

c) The probability of 3 or more faulty cell phones were produced in today's run is 0.2694

7 0

3 years ago

What is the difference between stem and leaf plot and dot plot?

antiseptic1488 [7]

Stem-and-Leaf-plot represents data by separating each value into two parts. Dot plot uses a graph in which each data value is plotted as a point along a horizontal scale of values. The difference is Dot Plots use graphs to organize data and Stem-and-Leaf plot separates the data into two parts

6 0

3 years ago

It rained 12 days out of 30 days. Which

aliya0001 [1]

The answer to your question is 4:10

3 0

3 years ago

Find the polynomial function in standard form that has the zeros listed. 1(multiplicity 2), -2(multiplicity 3)

finlep [7]

Answer:

f(x) = x⁵ +4x⁴ +x³ -10x² -4x+8

Step-by-step explanation:

If p is a zero, then (x -p) is a factor. The multiplicity of the zero tells you how many times that is a factor (its exponent).

f(x) = (x -1)²(x +2)³ = (x² -2x +1)(x³ +6x² +12x +8)

f(x) = x⁵ +4x⁴ +x³ -10x² -4x+8

_____

<em>Additional comment</em>

You can use the distributive property to write out the 12 terms of the product of the two expanded factors, or you can do a little mental arithmetic based on what you know about the exponent of a product term. (It is the sum of the exponents of its factors.)

The mental exercise can be made easier by writing the coefficients of the factors as though they were two cubics. It works well to write them in two rows:

$\left[\begin{array}{cccc}0&1&-2&1\\1&6&12&8\end{array}\right]$

The columns are in order of decreasing powers of x. A relatively simple and symmetrical pattern of sums of cross products is used to find the coefficients of the final polynomial. Working in order of decreasing exponents, we have ...

coefficient of x^6 = (0)(1) = 0

coefficient of x^5 = (0)(6) +(1)(1) = 1

coefficient of x^4 = (0)(12) +(1)(-2) +(1)(6) = 4

coefficient of x^3 = (0)(8) +(1)(1) +(1)(12) +(6)(-2) = 1

coefficient of x^2 = (1)(8) +(6)(1) +(-2)(12) = -10

coefficient of x^1 = (-2)(8) +(12)(1) = -4

coefficient of x^0 = (1)(8) = 8

5 0

3 years ago