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masya89 [10]
4 years ago
7

ANSWER QUICKK I JIST REALIZED IM GETTIN TIMED FULL QUESTION ATTACHED!

Mathematics
1 answer:
fenix001 [56]4 years ago
6 0

Plot what is on the chart

1 hour goes on the bottomx axis and 2 goes on the y axis going up . Keep doing for the rest ...the numbers under time go on x axis the line laying down....the distance numbers go on the line standing

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Tell whether the two ratios are proportional or not proportional 3/7=6/9
BlackZzzverrR [31]
NO they are not proportional

3/7 = .4285714
6/9 = .66666
7 0
3 years ago
Does anyone minding helping me with exterior angles ? due in 2 days
Goryan [66]

Answer:

x=25

Step-by-step explanation:

(x+40)+(3x+10)=6x

4x+50=6x

50=2x

25=x

5 0
3 years ago
Read 2 more answers
$119 coat ; 40% discount
Fudgin [204]
119 times .4 = 47.6

Hope this helped
8 0
4 years ago
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You want to estimate the mean weight loss of people one year after using a popular weight-loss program being advertised on TV. H
maria [59]

Answer:

At least 6907 people.

Step-by-step explanation:

Population std deviation = sigma= 10.6

Since population std deviation is known, we can use normal probability table to get sample size from confidence interval.

The sample mean weight loss is within 0.25 lb of the true population mean.

Hence  margin of error < 0.25

Margin of error = z critical (std dev/n) where n = sample size

Z critical for 95% = 1.96

Hence 0.25 >1.96(10.6)/sq rt n

Simplify to get

sq rt n > 1.96(10.6)/0.25 = 83.104

Square both the sides to get

n > 83.104 square = 6906.27

i.e. sample size should be atleast 6907.

3 0
3 years ago
Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr
dybincka [34]

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

3 0
3 years ago
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