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horrorfan [7]
3 years ago
13

Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr

action 3 StartRoot x EndRoot (x cubed + 4) Over 2 EndFraction log StartFraction 3 StartRoot x EndRoot (3 x + 4) Over 2 EndFraction log StartFraction StartRoot 9 x (x cubed + 4) EndRoot Over 6 EndFraction StartFraction StartRoot log 9 x ( x cubed + 4) EndRoot Over 6 EndFraction
Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

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60º

Step-by-step explanation:

The interior angles of a triangle equals 180º. And 60+60+60=180, that is your answer.

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How much force did the car apply to the golf cart?
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How much must be deposited today into the following account in order to have $ 50,000 in 6 years for a down payment on a​ house?
Charra [1.4K]

Answer:

The Amount initially deposited is $37046.64

Step-by-step explanation:

A = p (1+r/n)^(nt)

A= final amount= $5000

P = principal amount=

r = rate = 0.05

n = number of times compounded

= 6*12

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A = p (1+r/n)^(nt)

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The Amount initially deposited is $37046.64

3 0
4 years ago
Help please I-ready please
svlad2 [7]

Answer:

(5, 180)

Step-by-step explanation:

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What is the following quotient? StartFraction 6 minus 3 (RootIndex 3 StartRoot 6 EndRoot) Over RootIndex 3 StartRoot 9 EndRoot E
Bezzdna [24]

Exponent properties help us to simplify the powers of expressions.  The quotient of the given expression \dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}} is (2∛3 - ∛18).

<h3>What are the basic exponent properties?</h3>

{a^m} \cdot {a^n} = a^{(m+n)}\\\\\dfrac{a^m}{a^n} = a^{(m-n)}\\\\\sqrt[m]{a^n} = a^{\frac{n}{m}}\\\\(a^m)^n = a^{m\times n}\\\\(m\times n)^a = m^a\times n^a\\\\

Given to us

\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}

We will solve the problem using the basic exponential properties,

\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = \dfrac{6}{\sqrt[3]{9}} - \dfrac{3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = (6\cdot 3^{-\frac{2}{3}}) - [3 \cdot (2 \cdot 3)^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\= (2 \cdot 3 \cdot 3^{-\frac{2}{3}}) - [3 \cdot 2^{-\frac{2}{3}} \cdot 3^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\

= [2 \cdot 3^{(1-\frac{2}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(1+\frac{1}{3} - \frac{2}{3})}]\\\\=  [2 \cdot 3^{(\frac{1}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(\frac{2}{3})}]\\\\= 2\sqrt[3]{3} - \sqrt[3]{2}\sqrt[3]{9}\\\\=2\sqrt[3]{3} - \sqrt[3]{18}

Hence, the quotient of the given expression \dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}} is (2∛3 - ∛18).

Learn more about Exponents:

brainly.com/question/5497425

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3 years ago
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