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DaniilM [7]
3 years ago
9

The number of points that Shira scored each basketball game so far this season is shown on the dot plot. A number line going fro

m 1 to 13. 2 dots are above 2. 1 dot is above 3. 1 dot is above 5. 2 dots are above 7. 3 dots are above 9. 6 dots are above 11. 1 dot is above 12. Which statement must be true according to the dot plot?
Mathematics
2 answers:
REY [17]3 years ago
6 0

Answer:

the answer is A

Step-by-step explanation:

just took the test lol

romanna [79]3 years ago
3 0

Answer:

A: the data is skewed to the right and shows that she never scored fewer than 2 points or more than 12 points in a game

Step-by-step explanation:

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Im having a mental breakdown can someone please just do this for me
topjm [15]
The slopes of the original function y = |x| are m = 1 and m = -1 (m is the variable used to represent slope).

when you add a coefficient (number) in front of |x|, it will either make the slopes steeper or more flat. the larger the value of the coefficient, the steeper the slope will be (vice versa for a coefficient smaller than 1, which would make the slope more flat than the parent(original) function).

because these are absolute value functions, they will have two slopes. one slope for the end going up from left to right, and one for the end going down from left to right. this means that one slope must be positive and the other slope must be negative for each function.

with this in mind, the slopes of y = 2|x| are m = 2 and m = -2. the coefficient of 2 narrows the function by a factor of 2 (it is twice as narrow as the parent function). the same rules apply to y = 4|x| with the slopes of this function as m = -4 and m = 4 (it is 4 times narrower than the parent function).

with the fraction coefficients, the function is being widened. therefore, the slopes of y = 1/2 |x| are m = -1/2 and m = 1/2. the slopes of y = 1/5 |x| are m = -1/5 and m = 1/5.
6 0
2 years ago
MATH HELP PLEASE DRAW,, GEOMETRY ;3
Sophie [7]

E(1,-4)  F(1,-6)  G(-3,-5)  H(-3,-3)

7 0
3 years ago
Find the Area of the figure below, composed of a rectangle and a semicircle. Round to
chubhunter [2.5K]

Answer:

Area = 74.1 square units

Step-by-step explanation:

Area of the composite figure = Area of the rectangle + Area of the semicircle

Area o the rectangle = Length × Width

                                   = 10 × 6

                                   = 60 square units

Area of the semicircle = \frac{1}{2}\pi r^{2}

Here, r = radius of the semicircle

For the semicircle with radius = \frac{6}{2} = 3 units

Area = \frac{1}{2}\pi (3)^{2}

        = 4.5π

        = 14.14 units²

Total area of the composite figure = 60 + 14.14

                                                          = 74.14 square units                                                                                              ≈ 74.1 square units      

3 0
3 years ago
Solve the equation by using the Properties of Equality.<br> 9x – 3 = 42
Naya [18.7K]

Step-by-step explanation:

9x-3=42

9x=42+3

9x=45

9x/9=45/9

x=5

3 0
3 years ago
Please help me with the worksheet
aivan3 [116]

Answer:

9)    a = ¾, <u>vertex</u>: (-4, 2),  <u>Equation</u>: y = ¾|x + 4| + 2

10)  a = ¼, <u>vertex</u>: (0, -3),  <u>Equation</u>: y = ¼|x - 0| - 3

11)   a = -4,  <u>vertex</u>: (3,  1),   <u>Equation</u>: y = -4|x - 3| + 1

12)  a = 1,    <u>vertex</u>: (-2, -2),  <u>Equation</u>: y = |x + 2| - 2

Step-by-step explanation:

<h3><u>Note:</u></h3>

I could <u><em>only</em></u> work on questions 9, 10, 11, 12 in accordance with Brainly's rules. Nevertheless, the techniques demonstrated in this post applies to all of the given problems in your worksheet.

<h2><u>Definitions:</u></h2>

The given set of graphs are examples of absolute value functions. The <u>general form</u> of absolute value functions is: y = a|x – h| + k, where:

|a|  = determines the vertical stretch or compression factor (wideness or narrowness of the graph).

(h, k) = vertex of the function

x = h represents the axis of symmetry.

<h2><u>Solutions:</u></h2><h3>Question 9)  ⇒ Vertex: (-4, 2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (0, 5) and substitute into the general form (equation):

y = a|x – h| + k

5 = a| 0 - (-4)| + 2

5 = a| 0 + 4 | + 2

5 = a|4| + 2

5 = 4a + 2

Subtract 2 from both sides:

5 - 2 = 4a + 2 - 2

3 = 4a

Divide both sides by 4 to solve for <em>a</em>:

\LARGE\mathsf{\frac{3}{4}\:=\:\frac{4a}{4}}

a = ¾

Therefore, given the value of a = ¾, and the vertex, (-4, 2), then the equation of the absolute value function is:

<u>Equation</u>:  y = ¾|x + 4| + 2

<h3>Question 10)  ⇒ Vertex: (0, -3)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -2) and substitute into the general form (equation):

y = a|x – h| + k

-2 = a|4 - 0| -3

-2 = a|4| - 3

-2 = 4a - 3

Add 3 to both sides:

-2 + 3 = 4a - 3 + 3

1 = 4a  

Divide both sides by 4 to solve for <em>a</em>:

\LARGE\mathsf{\frac{1}{4}\:=\:\frac{4a}{4}}

a = ¼

Therefore, given the value of a = ¼, and the vertex, (0, -3), then the equation of the absolute value function is:

<u>Equation</u>:  y = ¼|x - 0| - 3

<h3>Question 11)  ⇒ Vertex: (3, 1)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -3) and substitute into the general form (equation):

y = a|x – h| + k

-3 = a|4 - 3| + 1

-3 = a|1| + 1

-3 = a + 1

Subtract 1 from both sides to isolate <em>a</em>:

-3 - 1 = a + 1 - 1

a = -4

Therefore, given the value of a = -4, and the vertex, (3, 1), then the equation of the absolute value function is:

<u>Equation</u>:  y = -4|x - 3| + 1

<h3>Question 12)  ⇒ Vertex: (-2, -2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (-4, 0) and substitute into the general form (equation):

y = a|x – h| + k

0 = a|-4 - (-2)| - 2

0 = a|-4 + 2| - 2

0 = a|-2| - 2

0 = 2a - 2

Add 2 to both sides:

0 + 2  = 2a - 2 + 2

2 = 2a

Divide both sides by 2 to solve for <em>a</em>:

\LARGE\mathsf{\frac{2}{2}\:=\:\frac{2a}{2}}

a = 1

Therefore, given the value of a = -1, and the vertex, (-2, -2), then the equation of the absolute value function is:

<u>Equation</u>:  y = |x + 2| - 2

5 0
2 years ago
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