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DaniilM [7]
3 years ago
9

The number of points that Shira scored each basketball game so far this season is shown on the dot plot. A number line going fro

m 1 to 13. 2 dots are above 2. 1 dot is above 3. 1 dot is above 5. 2 dots are above 7. 3 dots are above 9. 6 dots are above 11. 1 dot is above 12. Which statement must be true according to the dot plot?
Mathematics
2 answers:
REY [17]3 years ago
6 0

Answer:

the answer is A

Step-by-step explanation:

just took the test lol

romanna [79]3 years ago
3 0

Answer:

A: the data is skewed to the right and shows that she never scored fewer than 2 points or more than 12 points in a game

Step-by-step explanation:

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D?

Step-by-step explanation:

8 0
3 years ago
Write cot θ in reduced fraction form. (Picture included)
aleksandr82 [10.1K]
Tangent theta = opp/adj = 48/36 = 4/3
8 0
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7 is 5% of what number
Salsk061 [2.6K]

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Read 2 more answers
Find the slope of the line represented by the table. Show all work
wlad13 [49]
You are given the formula
m = (y2-y1)/(x2-x1)
You can pick any two points on table
Let’s choose (9,2) and (3,-2)
Plug in the values into formula
m = (-2-2)/(3-9)
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3 0
3 years ago
A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib
Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 502, \sigma = 115

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

Z = \frac{X - \mu}{\sigma}

Z = \frac{590 - 502}{115}

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 502}{115}

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

6 0
2 years ago
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