<span><span>The answer is 0.004. You are aware you could have just used a calculator or used google (Since you're posting on here you have access to the internet)</span><span>
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The rule for expressing a radical as a rational exponent is as follows:
![\sqrt[n]{x^y} = x^ \frac{y}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Ey%7D%20%3D%20x%5E%20%5Cfrac%7By%7D%7Bn%7D%20)
So, to find
![\sqrt[3]{27x^2y^3z^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27x%5E2y%5E3z%5E4%7D%20%20)
use that rule.
The cube root of 27 is 3, so the equation will start with 3.

Hope that helps!
Answer:
(0, 3)
Step-by-step explanation:
1. Find the slope:

2. Calculate the y-intercept using a given point:
(-8, -3)
-3 =
+ b
-3 = -6 + b
-3+6 = -6+6 + b
3 = b
3. Write in slope intercept form:

Therefore, the y-intercept is 3.
The graph for this table is shown below.
hope this helps :)
There is a trig identity called the sum of 2 angles for sin its<span>
sin(a+b)=sin(a)cos(b)+cos(a)(sin(b)
</span>
You will need to use it. So in your question split the 4x in 2 equal parts 2x and 2x
<span>
</span><span>sin(4x)=sin(2x+2x)
</span>Now using the expansion above you will get
<span>sin(2x+2x)=sin(2x)×cos(2x)+cos(2x)×sin(2x)
</span>And it will simplify to
<span><span>2sin(2x)cos(2x)
I hope this helps you! Good luck :)</span></span>