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3 years ago

9

Sarah wrote a computer program that generates two random numbers between one and nine. when she runs it, what is the probability

that both values will be six

1 answer:

Oksana_A [137]3 years ago

3 0

Answer:25/121

Step-by-step explanation:

You might be interested in

For a binomial probability distribution, it is unusual for the number of successes to be less than μ − 2.5σ or greater than μ +

kirill [66]

Answer:The correct option is a)

The upper limit of successes that would be deemed to be usual is 5, so more than 5 successes would be unusual.

Step-by-step explanation:

The mean of a binomial distribution

μ= np where n=10 and p= 0.2 q= 1-p, q= 1-0.2=0.8

μ= 10×0.2=2

σ=√npq

σ=√10×0.2×0.8=1.26

Is unusual for the number of success to be greater than μ + 2.5σ.

= 2+2.5(1.26)

=5 approximately.

So it is unusual for it to be greater than 0.5. The right option Is a)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%7C%5Csqrt%7B5%7D%20-%203%20%7C" id="TexFormula1" title="|\sqrt{5} - 3 |" alt="|\sqrt{5} - 3 |

quester [9]

Answer:

Calculate the sqr of 5 subtract it from 3 and find absolute value

Step-by-step explanation:

Sqr of 5 is 2.23606798

2.23606798 - 3 = -0.76393202

Absolute value of -0.76393202 is 0.76393202

8 0

3 years ago

Read 2 more answers

The equation y^2+8y−x+18=0 represents a parabola. Drag and drop the expressions into the boxes in the equation to rewrite the eq

mario62 [17]

Answer:

The equation of parabola is standard form is $x=\left(y+4\right)^2+2$

Step-by-step explanation:

Given equation of parabola is,

$y^2+8y-x+18=0$

In order to find the equation of parabola in standard form, eliminate x from left side of equation and use completing square method to find the equation.

First step is to add x on both side of equation.

$y^2+8y-x+18+x=0+x$

$y^2+8y+18=x$

Rewriting,

$x=y^2+8y+18$

Now applying completing square method as follows.

Following are the steps for calculation of this method.

Find the last term of above equation by using below formula,

$Last\:term\:of\:square=\left(\dfrac{coefficient\:of\:y}{2}\right)^{2}$

Now coefficient of y is 8.

$\therefore Last\:term\:of\:square=\left(\dfrac{8}{2}\right)^{2}$

Simplifying,

$Last\:term\:of\:square=\left(4\right)^{2}$

$Last\:term\:of\:square=16$

Second step is to add and subtract the last term.

$x=y^2+8y+18+16-16$

Rewriting,

$x=y^2+8y+16+18-16$

Since $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$

Using above formula,

$x=\left(y+4\right)^{2}+2$

Therefore, the equation of parabola in standard form is $x=\left(y+4\right)^{2}+2$

4 0

3 years ago

How do you factorise 6x-9

ankoles [38]

6x-9

factor 3 out of 6

factor 3 out of -9

Sector 3 - 2x + 3-3

3 X 2 - 3

please mark me as brainlist

5 0

3 years ago

Read 2 more answers

What are the factors of m2 – 6m + 6m – 36? (m – 2)(m + 18) (m – 3)(m + 3) (m – 4)(m + 9) (m – 6)(m + 6)

77julia77 [94]

<span>(m – 6)(m + 6) is the answer.
If you distribute them, you'll get </span><span>m^2 - 36</span>

3 0

3 years ago

Read 2 more answers