X^4-3x³+4x
x^4-3x³+3x+x
(x^4+x)-(3x³-3x)
x(x³+1)-3x(x²-1)
x(x+1)(x²-x+1)-3x(x+1)(x-1)
x(x+1)(x²-x+1-3x+3)
x(x+1)(x²-4x+4)
x(x+1)(x-2)(x-2)
so x intercepts are (0,0), (-1,0) and (2,0)
the y intercept is (0,0)
Hi there!
v = ±
- - - - - - - - -
K = 1/2mv²
Isolate for the variable "v". We can begin by dividing both sides by 1/2. (Multiply by the reciprocal, or 2):
2 · K = 2 · (1/2mv²)
2K = mv²
Continue isolating by dividing both sides by "m":
2K / m = v²
Take the square root of both sides. Remember that the solution can either be positive or negative since there are positive and negative roots.
v = ±
Answer:
x=28
Step-by-step explanation:
6(x+2)=180 Step 1: Write equation
6x+12=180 step 2: Expand the equation
6x=168 Step 3: Do 180-12 first
x=28 Step 4: Divide by 6 answer you got in Step 3
Step 5: replace 28 with x to see if it's correct 6(28+2)= 180
Put comment if answer is wrong and i will change my answer soon as possible
I hope this helps
Answer:
y=2/3x-8
Step-by-step explanation:
2x-3y=24
3y=2x-24
y=2/3x-24/3
y=2/3x-8
y=mx+b where m=slope and b=y-intercept.
Answer:
1. 
2. ![(p^2-6)[1-q(p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%28p%5E2-6%29%5D)
Step-by-step explanation:
1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.
Then the expression.
remains as:

2. The first thing to do to factor the expression is to take the expression
as its common factor with its lowest exponent.
Then the expression
remains as:
![(p^2-6)[1-q (p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%20%28p%5E2-6%29%5D)