Answer:
The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Step-by-step explanation:
The three different assembly lines are: A₁, A₂ and A₃.
Denote <em>R</em> as the event that a component needs rework.
It is given that:
Compute the probability that a randomly selected component needs rework as follows:
Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:
Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Answers:
The next two terms are 67.5 and 101.25 in that order.
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Explanation:
Divide the second term over the first to get 30/20 = 1.5
Divide the third term over the second term to get 45/30 = 1.5
The common ratio is 1.5, which means we multiply 1.5 by each term to get the next term
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fourth term = 1.5*(third term) = 1.5*45 = 67.5
fifth term = 1.5*(fourth term) = 1.5*67.5 = 101.25
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As a shortcut you can plug n = 4 and n = 5 into the function t(n) = 20*(1.5)^(n-1) to get the fourth and fifth terms respectively.
The slope can sometimes be called the gradient, and the equation for the gradient is (y2 - y1)/(x2 - x1). So therefore, you'd do: (-8 - 7)/(4 - -5) which is (-15)/9) which is -1 2/3 or -1.6 (recurring), which is your answer. I hope this helps! Let me know if I've confused you :)
I couldn’t see the whole picture so I’m not sure if I could really help I’m sorry maybe next time
