Question

P and q are points on the line 3y-4x=12 Complete the coordinates of p and q

Answer 1

Answer:

The points on the line 3 y - 4 x = 12 is  p = (0 , 4) , q = ( -3 , 0)  

Step-by-step explanation:

Given as :

The equation of line is

3 y - 4 x = 12

The points on the line are p , q

Now,

Let x = 0  

so, 3 y - 4 × 0 = 12

or, 3 y + 0 = 12

or, y = $\dfrac{12}{3}$

∴ y = 4

So, points p = (0 , 4)

Again

Let y = 0  

so, 3 × 0 - 4 × x  = 12

or, 0 -  4 × x  = 12

or, x = $\dfrac{- 12}{4}$

∴ x = - 3

So, points q = ( -3 , 0)

So, points are p = (0 , 4) , q = ( -3 , 0)

Hence The points on the line 3 y - 4 x = 12 is  p = (0 , 4) , q = ( -3 , 0)  Answer