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yanalaym [24]
4 years ago
12

Measure the length of the top of your desk in centimeters. Describe how you found the length.

Mathematics
2 answers:
Greeley [361]4 years ago
6 0
Take a ruler and put it on your desk and mesure from the centimeter side!!
seropon [69]4 years ago
5 0
You take the centimeter ruler or tape measure and you put one end on one end of your desk and the other on the other end. Simple!
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Write the sentence as an equation:<br> 30 is 369 more than w
OverLord2011 [107]

Answer:

30 = w + 369

Step-by-step explanation:

or

w + 369 = 30

8 0
3 years ago
The sum of 25 and z what’s the answer??
Rzqust [24]

Answer:25+Z

Step-by-step explanation:since your adding them

7 0
3 years ago
Solve 5(2y+1)=4y+10. this is for algebra 1
jolli1 [7]

Answer:

y=5/6\approx0.83

Step-by-step explanation:

So we have the equation:

5(2y+1)=4y+10

First, let's distribute the left side of our equation:

5(2y)+5(1)=4y+10

Multiply:

10y+5=4y+10

Now, let's isolate the y-variable. Subtract 4y from both sides:

(10y+5)-4y=(4y+10)-4y

The right side cancels. Subtract on the left. So:

6y+5=10

Now, subtract 5 from both sides:

(6y+5)-5=(10)-5

The left side cancels. Subtract on the right:

6y=5

Now, divide both sides by 6. So:

\frac{6y}{6}=\frac{5}{6}

The left will cancel. Therefore:

y=5/6\approx0.83

And we're done!

5 0
3 years ago
Read 2 more answers
Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips.Urn II contains three red
lorasvet [3.4K]

Answer:

P(R_{2}) =\frac{10}{15} = 0.667

Step-by-step explanation:

Step 1: Understanding the possible events

Selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be completed in two ways:

A. Selecting a red chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

B. Selecting a white chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

Therefore total probability is:

                                         P(R_{2}) = P(A) + P(B)

Step 2: Probability of selecting either chip from Urn I

Urn I contains 2 reds and 4 white chips, that gives a total of 6 chips.

                                             P(R_{1}) = \frac{2}{6} =\frac{1}{3}

                                             P(W_{1}) = \frac{4}{6} =\frac{2}{3}

Step 3: Probability of selecting a red chip from Urn II

Urn II originally contains 3 reds and 1 white chip, that gives a total of 4 chips.

Remember: Once a chip is added from Urn I to Urn II the total number of chips will increase in the Urn II

Case 1: When a red chip is added from Urn I to Urn II

Red chips    = 4

White chips = 1

Total Chips  = 5

                                                  P(R_{2_1}) = \frac{4}{5}

Case 2: When a white chip is added from Urn I to Urn II

Red chips    = 3

White chips = 2

Total Chips  = 5

                                                  P(R_{2_2}) = \frac{3}{5}

Therefore the total Probability of selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be calculated as:

                                          P(R_{2}) = P(A) + P(B)

                           P(R_{2}) = P(R_{1}) . P(R_{2_1}) + P(W_{1}) . P(R_{2_2})

                                           P(R_{2}) =\frac{1}{3} . \frac{4}{5}  + \frac{2}{3} .\frac{3}{5}

                                             P(R_{2}) =\frac{4}{15}  + \frac{2}{5}

                                            P(R_{2}) =\frac{10}{15} = 0.667      

8 0
3 years ago
Select the correct test statistic and critical value.
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

option A

5 0
3 years ago
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