You have to take out the GCF: 3(4a+7)
Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
First I would change the descriptions of the numbers into expressions.
first number is n
second number is n + 6
third number is 4n (4 x n)
Then you would insert these expressions into an equation and isolate n.
n + n + 6 + 4n = 144
n + n + 4n = 144 - 6
6n = 138
n = 138/6
n = 23
Lastly, you would plug in this value into all of the expressions.
first number is 23
second number is 23 + 6 = 29
third number is 4(23) = 92
Therefore, the numbers are 23, 29, and 92.
Answer:
$52.44
Step-by-step explanation:
Might be terribly wrong since it's been a while that I've done fractions, but I got -11/20. Hope this helps!!!