Answer:
20
Step-by-step explanation:
2 in 529 is in the tens place - 10
So if 2 is in the tens place, we have 20 as the value of 2.
Answer:
Step 1: Identify the Problem. ...
Step 2: Analyze the Problem. ...
Step 3: Describe the Problem. ...
Step 4: Look for Root Causes. ...
Step 5: Develop Alternate Solutions. ...
Step 6: Implement the Solution. ...
Step 7: Measure the Results.
Answer:
the expected value of this raffle if you buy 1 ticket = -0.65
Step-by-step explanation:
Given that :
Five thousand tickets are sold at $1 each for a charity raffle
Tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $500, 3 prizes of $300, 5 prizes of $50, and 20 prizes of $5.
Thus; the amount and the corresponding probability can be computed as:
Amount Probability
$500 -$1 = $499 1/5000
$300 -$1 = $299 3/5000
$50 - $1 = $49 5/5000
$5 - $1 = $4 20/5000
-$1 1- 29/5000 = 4971/5000
The expected value of the raffle if 1 ticket is being bought is as follows:





Thus; the expected value of this raffle if you buy 1 ticket = -0.65
Answer:
13
Step-by-step explanation:
243.50 - 130.50 = 104
104 ÷ 8 = 13
Answer:
39 students in the drama club, 25 in the yearbook club.
Explanation:
X=number of students in the drama club
Y=number of students in the yearbook club
X+Y=64
X−14=y
Subtract the equations
X−X+Y+14=64−Y
Y+14=64−Y
Subtract 14, add Y
Y+Y+14−14=64−14−Y+Y
2Y=50
Divide by 2
Y=25
X+25=64
Subract 25
X=64−25
X=39