What value of x makes this equation true? 6x/-4=6(-1/2) a) -2 b)2 c)3 d)-3

The amplitude of y = -3sinx is _____.

pishuonlain [190]

Answer:

The amplitude is 3.

Step-by-step explanation:

3 0

2 years ago

From a sample of 37 graduate students, the mean number of months of work experience prior to entering an MBA program was 35.15.

kiruha [24]

Answer: (29.35, 40.95)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

As per given , we have

$\overline{x}=35.15$

$\sigma=18$

n= 37

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, the confidence interval for the population mean will be :

$35.15\pm (1.96)\dfrac{18}{\sqrt{37}}$

$=35.15\pm (1.96)\dfrac{1.7}{6.08276}$

$=35.15\pm (1.96)(2.95918)$

$\approx35.15\pm5.80$

$=(35.15-5.80,\ 35.15+5.80)=(29.35,\ 40.95)$

Hence, a 95% confidence interval for the population mean = (29.35, 40.95)

8 0

2 years ago

PLEASE HELP 20 POINTS!!!!!!!!! The graph below shows a system of equations: Draw a line labeled y equals x plus 4 by joining the

Bogdan [553]

2 y = - x - 12 y = x + 5

- x - 1 = x + 5- 2 x = 5 + 1- 2 x = 6x = - 6 : 2x = - 32 y = - 3 + 52 y = 2y = 1The solution is ( - 3 , 1 ).Answer: x = - 3.

5 0

2 years ago

Read 2 more answers

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

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Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

2 years ago

Someone please help me with this one

Anna35 [415]

Answer:

k=-2x+9

Step-by-step explanation:

-4x+6=k*2x-3

+3 +3

-4x+9=k*2x

/2x /2x

-2x+9=k

8 0

2 years ago