What is -1.3 ≥ 2.9 -0.6r graph the solution

If a 35 ft rope is cut into two sections with one section 6 times as long as the other section, how long is the shorter piece?

Yuliya22 [10]

The smallest piece is 5ft, 5x6+5=35

4 0

3 years ago

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In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any

Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

$E \cap F = \emptyset,\quad E \cup F = \Omega$

where $\Omega$ is the whole sample space.

This implies that

$P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)$

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day $d_1$ .

The second footballer can be born on any other day, so he has 364 possible birthdays:

$d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}$

the probability for the first two footballers to be born on two different days is thus

$1 \cdot \dfrac{364}{365} = \dfrac{364}{365}$

Similarly, the third footballer can be born on any day, except $d_1$ and $d_2$ :

$d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}$

so, the probability for the first three footballers to be born on three different days is

$1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}$

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

$\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

So, the probability that at least two footballers are born on the same day is

$1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

since the two events are complementary.

8 0

3 years ago

The manager of a gas station has observed that the times required by drivers to fill their car's tank and pay are quite variable

maw [93]

Answer: 0.49

Step-by-step explanation:

The mean= E[x]=1/l= 7.5 min

l=1/7.5 =10/75=2/15

The exponential distribution's probability density function is looking like that:

F(x)= l*e^(-l*x) = 2/15*e^(-2*x/15)

P(0<x<5)= e^(-0*2/15)- e^(-5*2/15)=1- e^(-2/3)= approx 0.49

7 0

2 years ago

Please help me answer this

Solnce55 [7]

Answer:

i think you got that right its negative

Step-by-step explanation:

7 0

3 years ago

Parallel to y=−3x−2, through (-3, -3)

VashaNatasha [74]

Answer:

Use the formula y-y1=m(x-x1) <---memorize this. The m here is the slope.

Step-by-step explanation:

The equation is in y=mx+b form

Remember mx=slope and b=y-intercept

The question wants you to find the equation that is Parallel to y=-3x-2 and passes through (-3,-3)=(x1,y1)

Parallel=same slope -3x

So now all that's left is to plug into the equation.

y-(-3)=-3(x-(-3))

y+3=-3(x+3) ----> positive - a negative = positive so x-(-x)=x+x

y+3=-3x-9 ----> distribute like terms(subtract 3 from 3 and 3 from -9)

y=-3x-12 - This is your answer, you can check by graphing it.

Could i get Brainlest? thx :)

3 0

1 year ago