If flying with wind a small plane flew at 410 miles and 380 miles then the next step is to divide both speeds by two. This way you get the mph. So now it is 205 mph and 190 mph. Now we find the average of these two numbers and you get 197.5 mph.

7 0

3 years ago

In parallelogram EFGH, EJ = 6x + 3 and JG = 10x - 5 What is EG? A: 15 B: 12 C: 25 D: 30

Ne4ueva [31]

Answer:

D. 30

Step-by-step explanation:

It seems J is the intersection of diagonals.

We know diagonals of the parallelogram bisect each other.

It gives us:

EG = EJ + JG and
EJ = JG

Substitute and solve for x:

6x + 3 = 10x - 5
10x - 6x = 3 + 5
4x = 8
x = 2

Find the value of EJ:

EJ = 6*2 + 3 = 15

Find the value of EG:

EG = 2*EJ = 2*15 = 30

Correct choice is D

5 0

3 years ago

Read 2 more answers

What is the sum of 2x^2-x and -x-2x^2-2

Lorico [155]

<h2>Answer:</h2><h3>-2x-2</h3>

 $solution \\ {2x}^{2} - x + ( - x - {2x}^{2} - 2) \\ = {2x}^{2} - x - x - {2x}^{2} - 2 \\ = {2x}^{2} - {2x}^{2} - x - x - 2 \\ = - 2x - 2$ 

Hope it helps

Good luck on your assignment

5 0

3 years ago

Read 2 more answers