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-Dominant- [34]
3 years ago
10

What is -1.3 ≥ 2.9 -0.6r graph the solution

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0
Where are the choices?

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Explain the term least significant bit (LSB).
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the bit in a binary number which is the lowest numerical value

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Just subtract the number infront of missing number to the opposing number
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Solve inequality √(2−x) < x.
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[tex]\sqrt{2-x}0\\ x^2+2x-x-2>0\\ x(x+2)-1(x+2)>0\\ (x-1)(x+2)>0\\ x\in(-\infty,-2)\cup(1,\infty)\\\\ \boxed{x\in(-\infty,-2)\cup(1,2\rangle}[/tex]
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3 years ago
Simplify sqrt 244x + sqrt 36x - sqrt 25x
Morgarella [4.7K]
First simplify the square roots: 2 \sqrt{61x}+6 \sqrt{x}-5 \sqrt{x}
Then simplify the last two terms: 2 \sqrt{61x}+\sqrt{x}
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8 0
3 years ago
A parking lot charges $3 to park a car for the first hour and $2 per hour after that. If you use more than one parking space, th
fenix001 [56]
Consider the charge for parking one car for t hours.

If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.

If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.


75% is 75/100 or 0.75. 

For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be 

0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:

3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].


Thus, the function which total parking charge of parking 3 cars for t hours is:

</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1)) 


Answer: C</span>
4 0
3 years ago
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