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2 years ago

What is -1.3 ≥ 2.9 -0.6r graph the solution

Mathematics

1 answer:

Nat2105 [25]2 years ago

8 0

Where are the choices?

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B. 9.526 to the nearest tenth C. 19.826 to the nearest whole number

dimaraw [331]

B 9.5 to the nearest 10th
C 20 to the nearest whole number

8 0

2 years ago

Hello please help on number 3

padilas [110]

18 + 22 + 23 + 24 + 25 + 26 + 30= 168

168/7= 24

the missing number is 24

Good Luck! XD

3 0

3 years ago

Write th number of permutations in factorial form. then simplify. How many different ways can you and six of your friends sit in

kolbaska11 [484]

The answer is D. The answer is D because when It is simplified 7?49. The answer is the only possible answer could be correct since the rest of their maths don't add up.
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8 0

3 years ago

Vivi is a drummer for a band. She burns 756756756 calories while drumming for 333 hours. She burns the same number of calories e

alexandr1967 [171]

burned: 756 calories

hours: 3

same number of calories each hour

-> to find this, we must split the number of calories evenly among the hours

steps

756/3

= 252 calories per hour

6 0

3 years ago

Read 2 more answers

Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

2 years ago