Fill in the table using this function rule. y=30-4x X y 1 3 5 6 a

You can spend at most $50 on party snacks. You have spent $13 so far. Select an inequality that represents the additional amount

Marat540 [252]

Answer:

x ≤ $50 - $13

x ≤ $37

Step-by-step explanation:

please kindly check the attached file for explanation⇒

5 0

3 years ago

Read 2 more answers

What is 100 to the 20th power called?

dimulka [17.4K]

I think it is
1,000 quintillion

8 0

3 years ago

Read 2 more answers

Vertical and Adjacent Angles (3 Activities) 100 POINTS+BRAINLIEST

Yakvenalex [24]

Answer:

Problem B: x = 12; m<EFG = 48

Problem C: m<G = 60; m<J = 120

Step-by-step explanation:

Problem B.

Angles EFG and IFH are vertical angles, so they are congruent.

m<EFG = m<IFH

4x = 48

x = 12

m<EFG = m<IFH = 48

Problem C.

One angle is marked a right angle, so its measure is 90 deg.

The next angle counterclockwise is marked 30 deg.

Add these two measures together, and you get 120 deg.

<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.

Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.

m<G = 180 - 120 = 60

7 0

2 years ago

Read 2 more answers

I answered it but I just need someone to answer just to make sure mine are right

Artemon [7]

<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Given:

$m\angle Z = 138^{\circ}$

Note the following:

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

$m\angle 1 = 60^{\circ}$ (an angle in an equilateral triangle equals 60 degrees)

Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Learn more here:

brainly.com/question/2944195

5 0

2 years ago

Find the x- and y-intercept of the line x+4y=36

blagie [28]

Answer:

x=36

y=9

Step-by-step explanation:

Plug in 0 for x to find the y-intercept

0 + 4y = 36

4y = 36

y = 9

y-intercept (0, 9)

Plug in 0 for y to find the x-intercept

x + 4(0) = 36

x = 36

x-intercept (36, 0)

4 0

2 years ago