75% of apples have worm holes
Step-by-step explanation:
Given:
Total number of apples=12 apples
Number of apples with worm holes= 9 apples
To find:
Percentage of the apples have worm holes=?
Solution:
Substituting the values
Percentage of the apples have worm holes=75%
So you have to plug in the amount to the cost making you problem look like this:
0.85(30)+2.5(2)
25.5+5=30.5
Answer:
As per the statement:
Mr. Roseanne will buy 
pounds beef for for a cookout.
⇒ Weight of the beef he buy = 
pounds.
It is given that:
The price for the first 3 pounds of beef is $4.99 per pound.
then;
the price for 3 pounds he will pay= 
After that, the price is $4.49 per pound.
Remaining weight of beef left = 
pounds.
then;
the price of 
pounds he will pay = 
now, total money he will pay for the pounds beef = 
Therefore, $57.625 will Mr. Roseanne pay for the beef
Answer:
Anthony gave the sales clerk $40
Step-by-step explanation:
A = event the person got the class they wanted
B = event the person is on the honor roll
P(A) = (number who got the class they wanted)/(number total)
P(A) = 379/500
P(A) = 0.758
There's a 75.8% chance someone will get the class they want
Let's see if being on the honor roll changes the probability we just found
So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).
---------------
A and B = someone got the class they want and they're on the honor roll
P(A and B) = 64/500
P(A and B) = 0.128
P(B) = 144/500
P(B) = 0.288
P(A | B) = P(A and B)/P(B)
P(A | B) = 0.128/0.288
P(A | B) = 0.44 approximately
This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.
Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.
Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.
