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Alex777 [14]
3 years ago
15

What is the discriminant 3g^2+10= -15g

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
\bf 3g^2+10=-15g\implies 3g^2+15g+10=0
\\\\\\
\begin{array}{llcccll}
& 3g^2& +15g& +10\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac\implies 15^2-4(3)(10)
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What is the value of y?
RUDIKE [14]

Answer:

C. 55

Step-by-step explanation:

Since all angles in a triangle add up to 180°, we have:

40 + y + y + 30 = 180

2y + 70 = 180

2y = 110

y = 55

7 0
2 years ago
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On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), c
77julia77 [94]

The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76,  ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].

About a Graphed Function

The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.

It is evident from the attached graph that the supplied function exceeds 0 for the following range:

-0.7 < F(x) < 0.76

And, 0.76 < F(x) < ∞

As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,

(-0.7, 0.76) and (0.76, ∞)

Learn more about a graphed function here:

brainly.com/question/27757761

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3 0
1 year ago
5/8 times 12 and also simplified
Mars2501 [29]
0.63x12= 7.5 so the answer is 7.5
7 0
2 years ago
96.90+2.04-24.30 Round your answer to the nearest second decimal
frutty [35]

Answer:

74.64

Step-by-step explanation:

hope this helps :)

6 0
2 years ago
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The sum of three consecutive integers is −42. find the three integers.
erica [24]
Let the integers be x - 1, x and x + 1, then
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3x = -42
x = -42/3 = -14

The three consectutive integers are -15, -14 and -13
4 0
3 years ago
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