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JulijaS [17]
4 years ago
8

Copy the following number line, and mark each number on your number line. I've never been good with number lines!

Mathematics
2 answers:
faust18 [17]4 years ago
8 0

a) goes exactly in the middle between 4/10 and 5/10 on the numberline

b) exactly in the middle between 3/10 and 4/10

c) split the line in half between 7/10 and 8/10, then make a line at the center on the left side (basically split the line into 4 parts and mark it as the 1st line)

d/e/f) do the same as in C but between 2/10 and 3/10 

Assoli18 [71]4 years ago
5 0
I downloaded it and color-marked the answers on the numberline

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What expression represents the perimeter of the rectangle?<br> shown below
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4x + 4

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perimeter= breadth + length + breadth + length

(x+2)+(x+2)+x+x

= 4x(because there is 4 x) + 2 +2

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categorical ordinal

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The variable is categorical because not important, somewhat important and very important are three different categories and these categories are assigned numerical value 1,2 and 3 still numerical value assigning cannot lead to quantitative variable because 1 still means category not important. The scale of measurement in the variable is ordinal because it has meaningful order from category 1 not important to category 3 very important.

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An architect designs a rectangular flower garden such that the width is exactly two thirds of the length of 270 feet of an antiq
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3 years ago
Please help it’s urgent
katrin2010 [14]

\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

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4 years ago
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