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mamaluj [8]
3 years ago
10

The heights of apricot trees in an orchard are approximated by a normal distribution model with a mean of 18 feet and a standard

deviation of 1 feet. What is the probability that the height of a tree is between 16 and 20 feet
Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

0.9544

Step-by-step explanation:

We are given that mean=18 and standard deviation=1 and we have to find P(16<X<20).

P(16<X<20)=P(z1<Z<z2)

z1=(x1-mean)/standard deviation

z1=(16-18)/1=-2

z2=(x2-mean)/standard deviation

z2=(20-18)/1=2

P(16<X<20)=P(z1<Z<z2)=P(-2<Z<2)

P(16<X<20)=P(-2<Z<0)+P(0<Z<2)

P(16<X<20)=0.4772+0.4772=0.9544

The probability that the height of a tree is between 16 and 20 feet is 95.44%

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Virty [35]

Answer:

y = 9,958(0.972)^t

Step-by-step explanation:

From point to point, the difference in days is always constant (10 days), but the difference between estimated number of bees is not constant.

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From the other two options:

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only the first one has sense, because its initial amount of bees is 9,958 (near to 10,000) and in the second option is 0.972.

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3 years ago
PLEASE HELP! GIVING AWAY 20 POINTS TO BRAINLIEST ANSWER!
murzikaleks [220]
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Step-by-step explanation:

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2 years ago
Can someone help me with this math problem pls? will give thanks!
Tasya [4]

Answer:

sin(A) = opp / hyp

=a/hyp. =9/15

cos(A) = adj/hyp

=b/hyp. =12/15

Tan(A) = sin(A) / cos(A)

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