20
.......…......?7)$:&:&:7$:$;$;)$3$3$;$
Vertex is now at (-1,5)
for
y=a(x-h)^2+k
vertex is (h,k)
so veertex is (-1,5)
y=a(x-(-1))^2+5
y=a(x+1)^2+5
a is a constant, we will asssume that it is 1 because all the choices have 1
y=1(x+1)^2+5
y=(x+1)^2+5
2nd option
Answer:
9
Step-by-step explanation:
cuz i said
A) 60q/12
b) set ^ this equation equal to the one on the paper, move the variable to one side, and the rest should be easy from there
c) he loses profits
