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Black_prince [1.1K]
3 years ago
7

Annie wants to raise a pig for the county fair. The figure below is a diagram of what the pig pen will look like in order to fit

on the side of Annie’s house. In order to raise a pig, Annie needs to have a pig pen that is between 80ft2 to 100ft2.
What is the square footage Annie has available for the pig pen? Is this space big enough for her to raise a pig?
PLEASE HELP I WILL MARK BRAINLIEST IF POSSIBLE!!!!

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

30 to 50 more feet

Step-by-step explanation:

Add up all the sides to find the perimeter of the shape for the pen:

18 + 22.5 + 5 + 4.5 = 50

Since 50 is less than 80 to 100, then Annie has 30 to 50 more feet she can use for the pen.

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1/2 lemon per 1 cup

Step-by-step explanation:

6/6=1

3/6=1/2= .5 lemon

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8.94 inches

Step-by-step explanation:

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Step-by-step explanation:

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6 0
2 years ago
A piece of wire 28 ft long is cut into two pieces. One piece is used to form a square, and the remaining piece is used to form a
marusya05 [52]

Answer:

Wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

Step-by-step explanation:

Length of the wire = 28 ft has been cut in two pieces.

One piece is used to form a square and remaining piece to form a circle.

Let the length of the wire which forms the square is 'l' ft.

Area of the square = (side)²

Perimeter of the square = 4(side) = l

Length of one side = \frac{l}{4}

So, the area of the square = \frac{l^{2}}{16} ft²

Now length of the remaining part = perimeter of the circle = (28 - l) ft

2πr = (28 - l)

r = \frac{28-l}{2\pi }

Area of the circle formed = πr²

= \frac{\pi(28-l)^{2} }{4(\pi )^{2} }

= \frac{(28-l)^{2}}{4\pi }

Combined area of the square and circle

= \frac{l^{2}}{16} + \frac{(28-l)^{2}}{4\pi }

= \frac{l^{2}}{16} + \frac{(28-l)^{2}}{4\pi }

Now to maximize the area we will find the derivative of the area with respect to l.

\frac{dA}{dl}=\frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28-l)^{2}}{4\pi}]

= \frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28)^{2}+l^{2}-56l }{4\pi }]

= \frac{2l}{16}+\frac{(2l-56)}{4\pi }

Now equate the derivative to zero.

\frac{2l}{16}+\frac{(2l-56)}{4\pi } = 0

(2l-56)=-\frac{2l}{16}\times 4\pi

(2l-56)=-\frac{\pi l}{2}

2l+\frac{\pi l}{2}=56

\frac{(4l+l\pi )}{2}=56

l(4 + π) = 112

l(4 + 3.14) = 112

l = \frac{112}{7.14}

l = 15.69 ft

Length of the other part = 28 - 15.69 = 12.31 ft

Therefore, wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

8 0
3 years ago
Simplify the expression: (− 2/3 pq^4)^2·(−27p^5q)
VladimirAG [237]

Answer:

-12p^7q^9

Step-by-step explanation:

(-2/3Pq^4)^2×(-27P^5q)

= ((-2)^2)/3^2 × P^2 q^4-2 × (-27qp^5)

= ((-2)^2)/3^2 × 27p^7q9

= (((-2)^2 x 27p^7q9)/3^2

= -((4×27p^7q^9)/9)

= -(108p^7q^9)/9

= -12p^7q^9

4 0
3 years ago
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