We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
Answer:
01/6
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Step-by-step explanation:
Answer:
100 boys at the concert
Step-by-step explanation:
When changing the ratio between the number of boys to the number of girls, it always has to be equivalent to the original ratio 2:7
So, convert the ratio 2:7 to a different ratio, but it still has to be equivalent to the ratio 2:7. By doing that, multiply both sides of the 2:7 ratio by 50:
2 : 7
×50 ×50
To get:
100:350 ⇒ This ratio means that the ratio between the number of boys to the number of girls is now 100:350, but that’s okay to have because it’s still equivalent to the original 2:7 ratio.
So, using the new ratio 100:350, this means that there are 100 boys at the concert and 350 girls at the concert, and 350 is 250 more than 100 which proves what the question is asking. So there are 100 boys at the concert.
<u>Answer:</u> 100 boys at the concert
<em>I hope you understand and that this helps with your question! </em>:)
Answer:
28y^3 -35y^5
Step-by-step explanation:
= 7y^3(4) -7y^3(5y^2)
= 28y^3 -35y^5
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The applicable rule of exponents is ...
(y^a)(y^b) = y^(a+b)
