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4 years ago

27+45 gfc and distributive property

Mathematics

1 answer:

kompoz [17]4 years ago

4 0

The GFC is 9, but what would the distributive property be of?

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What is the value of 2x+3y when x=5 and y=2 ?

sesenic [268]

Answer:

Step-by-step explanation:

2(5) + 3(2)=

2x5=10

3x2=6

10+6=16

4 0

3 years ago

A construction company purchased

Nikolay [14]

Answer:

$ 1,968

Step-by-step explanation:

Boxes purchased = 246

Cost of 1 box = $ 8

Cost of 246 boxes

= 246 × 8

= $ 1,968

Hope it helps ⚜

8 0

3 years ago

Area of a circle<br> R = 5cm<br> Area=<br> REMEMBER TO ANSWER TO 2 DECIMAL PLACES.

Musya8 [376]

Answer:

78.52 cm sq.

Step-by-step explanation:

Area = pi x r^2

A = pi x (5)^2

A = pi x 25

A = 3.141 x 25

A = 78.52 cm sq.

4 0

4 years ago

A cone has a radius of 4 units and a height of 6 units. Its volume is (A. 96 / B. 100.48 / C. 301.44 / D. 401.92) cubic units. I

Fed [463]

Answer:

<h2>A cone: B. V = 100.48 cubic units</h2><h2>A cylinder: C. V = 301.44 cubic units</h2>

Step-by-step explanation:

The formula of a volume of a cone:

$V=\dfrac{1}{3}\pi r^2H$

<em>r</em> - radius

<em>H</em> - height

We have <em>r = 4 u</em> and <em>H = 6 u</em>. Substitute:

$V=\dfrac{1}{3}\pi(4^2)(6)=\dfrac{1}{3}\pi(16)(6)=\dfrac{1}{3}\pi(96)=32\pi\ u^3$

$\pi\approx3.14\to V\approx(32)(3.14)=100.48\ u^3$

If the cylinder has the same radius and height as a cone, then the volume of the cylinder is three times larger than the volume of the cone.

Therefore, the volume of acylinder:

$V\approx3(100.48)=301.44\ u^3$

Why?

The formula of a volume of a cone:

$V_{cone}=\dfrac{1}{3}\pi r^2H$

The formula of a volume of a cylinder:

$V_{cylinder}=\pi r^2H$

Therefore

$V_{cone}=\dfrac{1}{3}V_{cylinder}\to V_{cylinder}=3V_{cone}$

If the radius and height are the same.

8 0

3 years ago

Find the derivatives of the following implicit function

ddd [48]

Answer:

$\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

Step-by-step explanation:

$3x^2-6xy+y^2=2x-y\\\mathrm{Treat\:}y\mathrm{\:as\:}y\left(x\right)\\\mathrm{Differentiate\:both\:sides\:of\:the\:equation\:with\:respect\:to\:}x\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=\frac{d}{dx}\left(2x-y\right)\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(2x-y\right)=2-\frac{d}{dx}\left(y\right)\\6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)=2-\frac{d}{dx}\left(y\right)$

$\mathrm{For\:convenience,\:write\:}\frac{d}{dx}\left(y\right)\mathrm{\:as\:}y^{'\:}\\6x-6\left(y+xy^{'\:}\right)+2yy^{'\:}=2-y^{'\:}\\\mathrm{Isolate}\:y^{'\:}:\quad y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\\mathrm{Write}\:y^{'\:}\:\mathrm{as}\:\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

3 0

3 years ago