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Elanso [62]
2 years ago
15

Bill has two fat cats. He feeds each cat 150 grams of dry food each, twice a day. If he buys a 5 kilogram bag of dry food, about

how many days will the bag last?
Mathematics
1 answer:
Alinara [238K]2 years ago
6 0

Answer: 4 days (I think)

Step-by-step explanation:

One cat = 150*2 = 300g

Two cats = 600g

600*2 = 1200 (this is the total amount of food they both eat in a day)

5kg = 5000g

1200g/5000g = 4.17

The bag will last 4 days.

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Megans room was remodeled. The new area of the room is 175% of the previous area. Only the length of the room changed.
Alex17521 [72]

Answer:

As only the length of the room changed. It means the length of the room is increased by 175%, because of which the area is increased by 175%.

Therefore, the expression become

                                                             \frac{175}{100}\:l\cdot b

                                                             =1.75\:l\cdot b

And the area of Megan's room is increased by 0.75 square meters.

Step-by-step explanation:

  • Let l be the length of the room
  • Let b be the width of the room

So the area of the rectangle will be:

                                                         A=l\cdot \:b

As the statement mentions that the new area of the room is 175%% of the previous area.

So the new area of the room becomes:

                                                                 \frac{175}{100}\:l\cdot b

As only the length of the room changed. It means the length of the room is increased by 175%, because of which the area is increased by 175%.

Therefore, the expression become

                                                             \frac{175}{100}\:l\cdot b

                                                             =1.75\:l\cdot b

also

        \left(1.75\right)l\cdot \:b-\left(1\right)l\cdot \:b

         =0.75\:l\cdot b

so, the area of Megan's room is increased by 0.75 square meters.      

6 0
3 years ago
A Basketball Tournament starts with 128 Teams.in each round half of the teams are eliminated How Many teams remain after 5 round
Brrunno [24]

Total number of team in starting = 128 teams.

In each round half of the teams are eliminated.

Therefore, number of teams remain after first round = 128/2 = 64.

The number of teams remain after second round = 64/2 = 32.

The number of teams remain after third round = 32/2 = 16.

The number of teams remain after fourth round = 16/2 = 8.

The number of teams remain after fifth round = 8/2 = 4.

<h3>Therefore, after 5 rounds there remain only 4 teams.</h3>
8 0
3 years ago
Read 2 more answers
The outdoor temperature yesterday reached a low of -4.5 degrees Farenheit. Between what two intergers was the temperature?
valkas [14]
It was between -4 and -5
6 0
3 years ago
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Joe heard from a reliable source that only 22% of people actually sleep 8 hours or more per night. You do a survey and find 58 o
Juliette [100K]

Answer:

95% Confidence interval:  (31.32%,47.04%)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 148

Number of people who sleep for 8 hours or longer, x = 58

\hat{p} = \dfrac{x}{n} = \dfrac{58}{148} = 0.3918

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.3918\pm 1.96(\sqrt{\dfrac{0.3918(1-0.3918)}{148}})\\\\ = 0.3918\pm 0.0786\\\\=(0.3132,0.4704)=(31.32\%,47.04\%)

(31.32%,47.04%)  is the required 95% confidence interval.

8 0
3 years ago
In ABC, if m angle A
umka2103 [35]

Answer:

what

Step-by-step explanation:

3 0
3 years ago
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