Given: AB parallel to DC prove: ABE ~ DCE

2 answers:

8 0

The reasons would be:

alternate interior angles
vertical angles
AAA (all angles are congruent)

Since we know that the two line segments are parallel, this means that BC is a transversal. Using that knowledge with the position of ABE and DCE, we see these are alternate interior angles.

AEB and DEC are vertical angles, since they share only a vertex.

This gives us 3 congruent angles, so the triangles must be similar.

Vesna [10]3 years ago

3 0

Answer: The 3 missing statements are listed below with explanations.

2) Alternate interior angles are congruent. Since the lines are parallel these angles are congruent.

3) Vertical angles are congruent. Intersecting angles across from each other are congruent.

4) AA Similarity Theorem. If 2 angles of a triangle are congruent, then the triangles are similar.

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Step-by-step explanation:

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2 years ago

L=wh/a(w+p) Make w the subject of the formula

Anvisha [2.4K]

Answer:

w = lap/ h - la

Step-by-step explanation:

1 Multiply both sides by a(w+p)a(w+p).

la(w+p)=wh

2 Expand.

law+lap=wh

3 Subtract law from both sides.

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2 years ago

Convert into decimals (use your calculator): a) 6/38 b) 45/55 c) 4/28 d) 35/28 e) 1030/2030

Delicious77 [7]

Answer:

$a.\hspace{3} \frac{6}{38} = 0.15789474\\\\b.\hspace{3} \frac{45}{55} = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 0.14285714\\\\d.\hspace{3} \frac{35}{28} = 1.25\\\\e.\hspace{3} \frac{1030}{2030} = 0.50738916$

Step-by-step explanation:

Rational numbers, expressed as decimal numbers, are obtained from the operation of division between the integer of the numerator and the integer of the denominator. Then:

$a.\hspace{3} \frac{6}{38} = 6\div38 = 0.15789474\\\\ b.\hspace{3} \frac{45}{55} = 45\div55 = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 4\div28 = 0.14285714\\\\ d.\hspace{3} \frac{35}{28} = 35\div28 = 1.25\\\\ e.\hspace{3} \frac{1030}{2030} = 1030\div2030 = 0.50738916$