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ikadub [295]
4 years ago
7

Given: AB parallel to DC prove: ABE ~ DCE

Mathematics
2 answers:
slava [35]4 years ago
8 0
The reasons would be:

alternate interior angles
vertical angles
AAA (all angles are congruent)

Since we know that the two line segments are parallel, this means that BC is a transversal.  Using that knowledge with the position of ABE and DCE, we see these are alternate interior angles.

AEB and DEC are vertical angles, since they share only a vertex.

This gives us 3 congruent angles, so the triangles must be similar.
Vesna [10]4 years ago
3 0
Answer: The 3 missing statements are listed below with explanations.

2) Alternate interior angles are congruent. Since the lines are parallel these angles are congruent.

3) Vertical angles are congruent. Intersecting angles across from each other are congruent.

4) AA Similarity Theorem. If 2 angles of a triangle are congruent, then the triangles are similar.
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answer is 11.

Step-by-step explanation:

the median is always the middle

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What is the gcf of 48, 64 and 72
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The greatest common factor is 8 because Prime factor is 2 and 4, Number 48 is 4 and 1 Number 64 is 6 and o Number 72 is 3 and 0 which it would all equal 2^3  so 48 = 2^4 times 3 64 = 2^6 and 72 = 2^3 times 3^2 Hope this helps.

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balandron [24]
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Which number line shows 2 + (-5)?​
ladessa [460]

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-3

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7 0
3 years ago
I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
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