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serg [7]
3 years ago
7

Simplify 5т — п — 5п + 2

Mathematics
1 answer:
grigory [225]3 years ago
8 0

Answer:

5t-4n+2

Step-by-step explanation:

n-5n=-4n

5t-4n+2

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John takes out a personal loan for $5,000 at an annual interest rate 7.5%, compounded monthly. He plans to pay off the loan (inc
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155.53

Step-by-step explanation:

I know where this question is from hahaha

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5 magazines and 3 books cost $41.50. 2 magazines and 5 books cost $42.25. Find the cost of each item.
WINSTONCH [101]

Answer:

The Magazines each costed $8.30 and the books cost $13.80 for the amount of $41.50. and the 2 magazines and 5 books for $42.25 the 2 magazines is $21.12 for each and $8.45 for each book.

Step-by-step explanation:I got the answers by taking the total cost and taking the number of books or if it was a a magazine and I would divide it by lets just say you have 42.25 dollars you would divide that by 3 and you would do it for every item with the total cost.

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PLEASE I NEED URGENT HELP
kari74 [83]

Answer:

D

Step-by-step explanation:

the exterior angle ACD = m< 1+ m <2 = 56+54 = 110

6 0
3 years ago
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Express 1 − tan ⁡ θ sin ⁡ θ cos ⁡ θ in terms of cos ⁡ θ .
allsm [11]

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cos^2(theta)

8 0
2 years ago
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The distribution of the amount of money in savings accounts for University of Alabama students has an average of 950 dollars and
Pavlova-9 [17]

Answer:

Approximately Normal, with a mean of 950 and a standard error of 158.11

Step-by-step explanation:

To solve this question, we need to understand the Central Limit Theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 950, \sigma = 1000

The sampling distribution of the sample mean amount of money in a savings account is

By the Central Limit Theorem, approximately normal with mean \mu = 950 and standard error s = \frac{1000}{\sqrt{40}} = 158.11

So the correct answer is:

Approximately Normal, with a mean of 950 and a standard error of 158.11

8 0
3 years ago
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