Is this a question or an answer
4.3 Solving 3x2-2x-1 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 3
B = -2
C = -1
Accordingly, B2 - 4AC =
4 - (-12) =
16
Applying the quadratic formula :
2 ± √ 16
x = —————
6
Two real solutions:
x =(2+√16)/6
or:
x =(2-√16)/6
Answer:
<h2>
A. 1/6^2</h2>
Step-by-step explanation:
6^3/6^6 = 1/216
1/6^2 = 1/36 ≠ 1/216
1/6^3 = 1/216
what numbers are betwwen 2 and 5? ......<em> 3 and 4</em>
and 
You can check this by converting them into decimals.
= .50
= .33
= .25
= .20
Answer: and
Technically speaking, because the way you have the question written, in words the equation would be said as y equals one-thirds multiplied by the absolute value of x, then minus two. Properly saying as y equals two less that the product of one-third and the absolute value of x.
The absolute value is the distance away from 0 therefor the value would alway equal as a positive value. EX1: |21| = 21 EX2: |-21| = 21
even if you considered -2 within y=1/3|x|-2 as -2 being negative two instead of minus two, then it would be the same meaning in the case that you have written out in a mathematical equation format, but really because -2 comes after 1/3|x| and -2 is not in parenthesis then it would make more since to say minus two.
