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anzhelika [568]
4 years ago
9

A bakery sold 101 cupcakes in one day. The head baker predicted he would sell 81 cupcakes that day. What was the percent error o

f the baker's prediction? *
Mathematics
1 answer:
Hoochie [10]4 years ago
6 0

Answer:

19.8% is the percent error of the baker's prediction.

Step-by-step explanation:

We are given the following in the question:

Total number of cupcakes sold in 1 day = 101

Predicted number of cupcakes sold = 81

We have to find the percent error of the baker's prediction.

Percentage error =

=\dfrac{\text{Actual value - Predicted value}}{\text{Actual values}}\times 100\%

Putting values, we get

=\dfrac{101-81}{101}\times 100\%\\\\=19.8\%

Thus, 19.8% is the percent error of the baker's prediction.

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7 0
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Suppose that r1 and r2 are roots of ar2 + br + c = 0 and that r1 = r2; then exp(r1t) and exp(r2t) are solutions of the different
Nady [450]

The Correct Question is:

Suppose that r1 and r2 are roots of ar² + br + c = 0 and that r1 = r2; then e^(r1t) and e^(r2t) are solutions of the differential equation

ay'' + by' + cy = 0.

Show that

φ (t; r1, r2) = [e^(r2t) - e^(r1t )]/(r2 - r1)

is a solution of the differential equation.

Answer:

φ (t; r1, r2) is a solution of the differential equation, and it shown.

Step-by-step explanation:

Given the differential equation

ay'' + by' + cy = 0

and r1 and r2 are the roots of its auxiliary equation.

We want to show that

φ (t; r1, r2) = [e^(r2t) - e^(r1t )]/(r2 - r1)

satisfies the given differential equation, that is

aφ'' + bφ' + cφ = 0 .....................(*)

Where φ = φ (t; r1, r2)

We now differentiate φ twice in succession, with respect to t.

φ' = [r2e^(r2t) - r1e^(r1t )]/(r2 - r1)

φ'' = [r2²e^(r2t) - r1²e^(r1t )]/(r2 - r1)

Using these in (*)

We have

a[r2e^(r2t) - r1e^(r1t )]/(r2 - r1) + [r2²e^(r2t) - r1²e^(r1t )]/(r2 - r1) + c[e^(r2t) - e^(r1t )]/(r2 - r1)

= [(ar2² + br2 + c)e^(r2t) - (ar1² + br1 + c)e^(r1t)]/(r1 - r2)

We know that r1 and r2 are the roots of the auxiliary equation

ar² + br + c = 0

and r1 = r2

This implies that

ar1² + br1 + c = ar2² + br2 + c = 0

And hence,

[(ar2² + br2 + c)e^(r2t) - (ar1² + br1 + c)e^(r1t)]/(r1 - r2) = 0

Therefore,

aφ'' + bφ' + cφ = 0

7 0
3 years ago
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