Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Use a system of equations:
For his trip on the way there:
D = 7*s
For his trip on the way home you have:
D = 5*(s+18)
use substitution to solve
Answer:
49π
Step-by-step explanation:
area of circle = πr^2
<em>Handy Tip: cherry pies delicious; apple pies are(R) too(2)! so C = πd and A = πr^2</em>
diameter = 14 cm
radius = 14/2 = 7cm
area of circle = π(7)^2
area of circle = 49π
Hope that helps!
Answer:
X=±8
Step-by-step explanation:
x²=64
x²=8²
X=±✓8²
X=±8
Answer:
Area of the shaded portion = (120π + 36√3)sq. m
Step-by-step explanation:
Area of the shaded region = Area of circle - Area of triangle
Given
radius of the circle = 12m
Area of the circle = πr²
Area of the circle = π(12)²
Area of the circle = 144π m²
Area of the sector = theta/360 * πr²
Area of the sector = 60/360 * 12²π
Area of the sector = 60/360 * 144π = 24π
Area of the triangle = 1/2 bh
Area of the triangle = 1/2 (12cos30)(12)
Area of the triangle = 36√3
Area of the shaded portion = (144π - 24π + 36√3)sq. m
Area of the shaded portion = (120π + 36√3)sq. m
