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Goshia [24]
3 years ago
9

PLEASE help me. This is due today

Mathematics
2 answers:
insens350 [35]3 years ago
7 0

Answer:

A. A negative linear association

Step-by-step explanation:

The points are close enough for a line of best fit, therefore they are linearly associated and they are going down so it is negative association.

MrRa [10]3 years ago
3 0

Answer:

negative linear

Step-by-step explanation:

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Step-by-step explanation:

First add 11 then -69

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And an electronics warehouse ships TVs and DVD players to retailers all throughout the United States. The weight of three televi
vodomira [7]
X= weight of TV
y= weight of CD

3x+5y= 62.5
3x+ 2y= 52
You can either solve for a variable, or eliminate a variable by subtracting the second equation from the first:

3x + 5y = 62.5
-(3x+2y = 52)
0 + 3y = 10.5, so y = 10.5/3 or 3.5.

Now plug y= 3.5 back into any equation to get x:

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3 years ago
Evaluate. Please help me!!!
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Keith bought a package with 2 l pounds
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100 POINTS PLZ HELPPP Drag each tile to the correct box. Arrange the expressions in increasing order of their estimated values.
andrew11 [14]

Answer:

<h3>\frac{\sqrt{24}- \sqrt{54} }{\sqrt{6}} = -1   </h3><h3>\sqrt{\frac{9}{20}*\frac{10\sqrt{2} }{3\sqrt{5} } = 1.4142</h3><h3>\frac{10\pi\sqrt{2}-8\pi\sqrt{2}}{2\sqrt{2}}  = π =3.14159</h3><h3>\pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}} = π² = 9.8696</h3>

Explanation:

1.) Rewrite √24 = \sqrt{4*6} = 2\sqrt{6}   Rewrite √54 =\sqrt{9*6}= 3\sqrt{6}

Divide both terms by the denominator; √6 cancels. 2-3 = -1

2.) Rewrite as \frac{3}{2\sqrt{5}} ×\frac{10\sqrt{2}}{3\sqrt{5}}  The 3's cancel.  10/2 = 5√2 in the numerator.

√5 × √5 = 5 in the denominator.  The 5's cancel.

That leaves √2 ≈1.4142

3.) Divide the terms in the numerator by the term in the denominator.

√2's cancel.  10π/2 = 5π   8π/2 = 4π  

Subtract and we are left with π = 3.14159

4.) \pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}}  The square roots are reciprocals. They multiply to 1

We are left with π × π = π² ≈  9.8696

<h3> </h3>

8 0
3 years ago
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