0,2 because the y intercept is th middle line so you go up the line and see what number the line goes through
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
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The rate of change in this pattern is 2:1 comparing the change in 'y' to the change in 'x'.. this means that if you go form 33 to 51 ( an increase of 18), then the the increase from 16 to ? will be 9. Therefore, ? = 16 + 9 or 25
? = 25
Answer: If the answer needs to be simplified, then the answer would be
-20c^2 d^3 - 16cd^2
Step-by-step explanation:
Answer:
They "y" value = (4 * 24) + 4 which equals
100
Step-by-step explanation: