Select the correct answer from each drop-down menu. Factor the trinomial. The factors of m2 + 12m + 35 are ( ) and ( ).
2 answers:
Answer:
![(m+5)(m+7)](https://tex.z-dn.net/?f=%28m%2B5%29%28m%2B7%29)
Step-by-step explanation:
Factor the trinomial. The factors of ![m^2 + 12m + 35](https://tex.z-dn.net/?f=m%5E2%20%2B%2012m%20%2B%2035)
In the given trinomial , the product is 35 and sum is 12
LEts find out two factors whose product is 35 and sum is 12
7 times 5 is 35
7 plus 5 is 12
Break the middle term using factors 7 and 5
![m^2 + 12m + 35](https://tex.z-dn.net/?f=m%5E2%20%2B%2012m%20%2B%2035)
![m^2 + 7m+5m + 35](https://tex.z-dn.net/?f=m%5E2%20%2B%207m%2B5m%20%2B%2035)
Group first two terms and last two terms
![(m^2 + 7m)+(5m + 35)](https://tex.z-dn.net/?f=%28m%5E2%20%2B%207m%29%2B%285m%20%2B%2035%29)
Take out GCF from each group
![m(m+7)+5(m + 7)](https://tex.z-dn.net/?f=m%28m%2B7%29%2B5%28m%20%2B%207%29)
FActor out m+7
![(m+5)(m+7)](https://tex.z-dn.net/?f=%28m%2B5%29%28m%2B7%29)
m^2 + 12m + 35
We can factor using the sum-product, when the sum of 2 numbers is 12 and the product of those 2 numbers is 35.
7+5 = 12
7 x 5 = 35
So we have the numbers 7 and 5.
m^2 + 12m + 35 = (m+7)(m+5)
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The arithmetic sequence with the given condition is determined recursively by
![\begin{cases}a_1=5\\a_n=a_{n-1}+3&\text{for }n>1\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Da_1%3D5%5C%5Ca_n%3Da_%7Bn-1%7D%2B3%26%5Ctext%7Bfor%20%7Dn%3E1%5Cend%7Bcases%7D)
So we have
![a_2=a_1+3](https://tex.z-dn.net/?f=a_2%3Da_1%2B3)
![a_3=a_2+3=a_1+3(2)](https://tex.z-dn.net/?f=a_3%3Da_2%2B3%3Da_1%2B3%282%29)
![a_4=a_3+3=a_1+3(3)](https://tex.z-dn.net/?f=a_4%3Da_3%2B3%3Da_1%2B3%283%29)
and so on with the general pattern
![a_n=a_1+3(n-1)](https://tex.z-dn.net/?f=a_n%3Da_1%2B3%28n-1%29)
This means the 72nd term in the sequence is
![a_{72}=a_1+3(72-1)=5+3(71)=218](https://tex.z-dn.net/?f=a_%7B72%7D%3Da_1%2B3%2872-1%29%3D5%2B3%2871%29%3D218)
so the answer is B.
Answer:
5
Step-by-step explanation:
5÷1
i m not sure but i like its ans
Answer:
41/500.
Hope it helps :) .
Answer:
25 gallons of sulfuric acid
Step-by-step explanation:
Find how much sulfuric acid is in the tank by finding 50% of 50 (the total gallons of solution):
50(0.5)
= 25
So, there are 25 gallons of sulfuric acid.