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Ratling [72]
2 years ago
6

On a baseball

Mathematics
1 answer:
vampirchik [111]2 years ago
4 0

Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

<h3>How far did the outfielder throw the ball?</h3>

Based on the shape of a mound, the law of cosines can be used.

The distance the ball was thrown by the outfielder can therefore be d.

Distance is:

d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))

d ²= 33,484.42ft

Then find the square root:

d = √33,484.42

= 182.9874

= 183 ft

Find out more solving for distance at brainly.com/question/10739348

#SPJ1

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Data given and notation  

\bar X=3.8 represent the sample mean

s=0.5 represent the sample standard deviation for the sample  

n=15 sample size  

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p_v represent the p value for the test (variable of interest)  

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We need to conduct a hypothesis in order to check if the mean weight is less than 4 ounces, the system of hypothesis would be:  

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If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

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Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549    

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Step-by-step explanation:

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