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Ratling [72]
2 years ago
6

On a baseball

Mathematics
1 answer:
vampirchik [111]2 years ago
4 0

Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

<h3>How far did the outfielder throw the ball?</h3>

Based on the shape of a mound, the law of cosines can be used.

The distance the ball was thrown by the outfielder can therefore be d.

Distance is:

d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))

d ²= 33,484.42ft

Then find the square root:

d = √33,484.42

= 182.9874

= 183 ft

Find out more solving for distance at brainly.com/question/10739348

#SPJ1

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Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

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4 years ago
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58 x 64 is the same as:
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