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disa [49]
3 years ago
7

(x^2+10x+26)/(x+6) How do you get the quotient and remainder

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

quotient is x+4 and remainder 2.

Step-by-step explanation:

Given an polynomial of degree 2 and we are to divide it by x+6.

To find quotient and remainder

We can do synthetic division

When we divide by x+6 consider -6

and write on left.  Write the coefficient 1 , 10, 26 inside

-6       1      10     26

         x       -6    -24

       ---------------------

          1      4       2 =R

So remainder is 2 and quotient is x+4

Let us verify

(x+4)(x+6) = x^2+10x+24

If we add the remainder we are getting the given expression.

x^2+10x+26

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Answer:

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Step-by-step explanation:

Considering the geometric sequence

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a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

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The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

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Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
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