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3 years ago

How can u use a number line to find the sum of -4 and 6

Mathematics

2 answers:

MrRa [10]3 years ago

8 0

Look at -4 on a number line then you add 6 spaces to the right which would get you 2

sdas [7]3 years ago

5 0

Find -4 on the number line.

Go to the right 6 place values (+6)

You will find your answer

-4 (+6) = 2

2 is your answer

hope this helps

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Write equations for the horizontal and vertical lines passing through the point (4, -5).

raketka [301]

Answer:

Horizontal line: y=-5

Vertical line: x = 4

Step-by-step explanation:

As we have to determine the equations for the horizontal and vertical lines passing through the point (4, -5).

To determine the equation for the horizontal line passing through the point (4, -5), we must observe that the horizontal line will always have the same y-value regardless of the x-value.

Therefore, the equation of the horizontal line passing through the point (4, -5) will be: y=-5

To determine the equation for the vertical line passing through the point (4, -5), we must observe that the vertical line will always have the same x-value regardless of the y-value.

Therefore, the equation of the vertical line passing through the point (4, -5) will be: x=4

Hence:

Horizontal line: y=-5

Vertical line: x = 4

8 0

3 years ago

MissTica

Answer:

$3.98(estimated)

Step-by-step explanation:

3c (cake) + 2(2c - 11) (bread) = 5.87

3c + 4c - 22 = 5.87

7c - 22 = 5.87

7c = 5.87 + 22

7c = 27.87

c = 3.98

6 0

2 years ago

The ratio of men to women working for a company is 5 to 7 if there are 133 women working for the company what is the total numbe

Mrrafil [7]

228 employees in total

6 0

3 years ago

Reduce to simplest form<br> 3/2 + ( -6/5 ) = ?

frosja888 [35]

Answer:

Step-by-step explanation: 3/2=1.5 (-6/5)=(-1.2) 1.5+(-1.2)=0.3

Answer=0.3

5 0

2 years ago

Read 2 more answers

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers