2(2y^4 + 7y^3 - 4y^2 -20)
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Y^2
4y^2 - 40/y^2 + 14y - 8
2(-2y^4 - 7y^3 + 4y^2 + 20)
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Y^2
Answer:
3.1 3.25 3.33 3.4
Step-by-step explanation:
Use the calculator to find:
169^2=169*169=28561
With the given hint to be able to answer the question above, the equation for Newton's law of cooling is as follows:
T(t) = T(s) + (T0 - Ts)e^-kt
where T(t) is the body's temperature at any given time, Ts is the temperature of the surrounding, T0 is the initial temperature, and k is constant.
Substituting the values with the given above,
T(t) = 76 + (170 - 76)*e^(-0.34)(7)
This gives us the answer,
T(t) = 84.7 degrees F
First of all, x>y
x-y=40
and
x+y=66
add them equations together to eliminate
x-y=40
<u>x+y=66 +</u>
2x+0y=106
2x=106
divide by 2
x=53
sub back
x-y=40
53-y=40
minus 53 both sides
-y=-13
y=13
the numbers are 53 and 13
