Answer:
<u>There can be 180 apples in that box.</u>
Step-by-step explanation:
1. Let's review the information given to answer the question correctly:
Number of apples in a box < 200
2. It is known that 2, 3, 4, 5, or 6 kids can share these apples evenly. How many apples can be in that box?
The answer is that the number of apples that can be in the box is the highest multiple of 2, 3, 4, 5, and 6 that is close to 200.
The common multiples for this set of numbers are 60, 120, 180, 240, 300 and so on with 60 as the constant.
Therefore, the highest number that is multiple for this set of numbers and at the same time lower than 200 is 180.
<u>There can be 180 apples in that box.</u>
Answer:
-7x≥-21
Solution:
-7x ≥ -21
÷-7 ÷-7
flip the sign when we divide by a negative number
x ≤ 3
≥ and ≤ mean closed dot
Answer:
4/15
Step-by-step explanation:
7/15 - 3/15 = 4/15
<span>n 19 -----------> AB/AC=(4/6)=2/3<span>
n 20 ------------> BC/CD=[AC-AB]/[AD-AC]=(6-4)/(9-6)=2/3
n 21-------------> BD/AE=[AD-AB]/[AE]=(9-4)/(12)=5/12
n 22 7 and 28 find the geometric mean of the two number
step 1
Multiply the two numbers together:
28*7=196
step 2
take the square root:
<span><span>sqrt(196)=14
</span>the answer is 14</span>
n 23 Simplify the ratio 10 ft/30 in---> divided between 2 both members
5 ft/15 in-----> divided between 5 both members ---> 1 ft/3 in</span><span>
n 24
<span>if AB=4 -------></span></span> AB~FG
</span><span>FG=8<span>
then
</span></span>AB*factor=FG-------- > 4*factor=8-- > factor=8/4=2
the figure ABCDE is half of the figure FGHJK
then<span>
BC=4
AE=CD=5
and
ED=6
therefore
<span>the perimeter=[4+4+5+5+6]=24 units</span></span>
18 meters by 14 meters
Step-by-step explanation:
18 meters by 14 meters
Area of rectangle is base times height (AKA length times width or however you wish to call the dimensions).
This question is a system of equations question. We can make two equations. We know that every rectangle must have 2 "lengths" and 2 "widths" (4 sides in a rectangle). Since Maria only has 64 meters of fencing, we get the equation:
2L+2W = 64
Now we know the area enclosed must be 252 so we have:
L* W = 252
Rewriting the second equation we get:
Plug this into first equation to get:
(multiply everything by L)
Solving the quadratic tells us L can be 18 or 14. Let's consider if L is 18 first by plugging 18 back into the second equation to get 18 * W = 252 which gives us W = 14. If we do the same for when L = 14, we get that W = 18.
Now you might wonder why we have 2 possible combinations, that's because in reality, it doesn't matter which one we label as length (L) or width (W).
