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jeyben [28]
3 years ago
11

A square has an area that is less than 100m^2. What is a reasonable range for the graph of the squares side

Mathematics
1 answer:
zloy xaker [14]3 years ago
8 0
In algebra, an equation is always formed by at least two variables: the dependent and independent. The independent variable are the ones you manipulate, or the ones you could directly measure. In this case, the independent variable is the side length. The dependent variable is the one that changes with the independent variable - which is the area. The equation for the area of the square is:

A = s^2, where s is the side length of the square

So, when the area does not exceed 100 m^2, then the upper limit is 100. Thus, the maximum side should be

100 > s^2
s < 10 m

The range is the coverage of the dependent variable. With that being said, the range is therefore from 0 to 100 square meters. Negative values are impossible so the lower limit is 0.
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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
Can someone please explain step by step on how I can get the answer? If so I’ll mark you brainliest
krok68 [10]

Answer:

3

Step-by-step explanation:

18 factors to 2, 3, 3

45 factors down to 5,3,3

6 0
3 years ago
AEFG is located at E (0,0), F (-7, 4), and G (0,8). Which statement correctly classifies AEFG?
viva [34]

Answer:

ΔEFG is an isosceles triangle

Step-by-step explanation:

8 0
3 years ago
Omar drew a number line that went from -10 to 10 and used it to compare integers. Which statement is true?
Evgen [1.6K]

Answer:

-7 < -3 because -7 is located to the left of -3 on a number line.

Step-by-step explanation:

This is because -7 is on the left of the -3. In negatives -3 is greater than -7. If it was positive then 7 would be greater than 3. So the answer is A. -7 < -3 because -7 is located to the left of -3 on a number line

4 0
3 years ago
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
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