Answer:
Step-by-step explanation:
Let s represent the speed of the bus.
From the information given, the bus needs to cover a distance of 240 km in less than 5 hours. The formula for calculating the speed of the bus, s is expressed as
Speed, s = distance covered by the bus/ time taken to cover the distance
Therefore,
Speed, s = 240/5 = 48 km/hr
A higher speed would ensure the bus covers the distance in less than 5 hours. Therefore, the inequality that represents the speed (s) of the bus would be
s ≥ 48
Mr Wellborn arrives at work at 7:50 am. If you take 60 minutes away from 8:40 its 7:40 but take away 10 minutes and its 7:50.
This is called the median.
Answer: Choice A)
![H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7BSA%7D%7B2%28L%2BW%29%7D%20-%20%5Cfrac%7BLW%7D%7BL%2BW%7D%5C%5C%5C%5C)
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Work Shown:
![SA = 2(LW + LH + HW)\\\\2(LW + LH + HW) = SA\\\\LW + LH + HW = \frac{SA}{2}\\\\LH + HW = \frac{SA}{2} - LW\\\\H(L + W) = \frac{SA}{2} - LW\\\\H = \frac{\frac{SA}{2} - LW}{(L + W)}\\\\H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\](https://tex.z-dn.net/?f=SA%20%3D%202%28LW%20%2B%20LH%20%2B%20HW%29%5C%5C%5C%5C2%28LW%20%2B%20LH%20%2B%20HW%29%20%3D%20SA%5C%5C%5C%5CLW%20%2B%20LH%20%2B%20HW%20%3D%20%5Cfrac%7BSA%7D%7B2%7D%5C%5C%5C%5CLH%20%2B%20HW%20%3D%20%5Cfrac%7BSA%7D%7B2%7D%20-%20LW%5C%5C%5C%5CH%28L%20%2B%20W%29%20%3D%20%5Cfrac%7BSA%7D%7B2%7D%20-%20LW%5C%5C%5C%5CH%20%3D%20%5Cfrac%7B%5Cfrac%7BSA%7D%7B2%7D%20-%20LW%7D%7B%28L%20%2B%20W%29%7D%5C%5C%5C%5CH%20%3D%20%5Cfrac%7BSA%7D%7B2%28L%2BW%29%7D%20-%20%5Cfrac%7BLW%7D%7BL%2BW%7D%5C%5C%5C%5C)
This is not the only way to solve for H.
Answer:
Step-by-step explanation
3x-15=2x-10+x
3x-15=3x-10
in this step, problem happens
becoz both side doesnt equal, no ans can be proven