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3 years ago

How many strings of eight english letters are there

Mathematics

1 answer:

Alex17521 [72]3 years ago

8 0

D because I answered it at school and it was correct

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In a certain card game you draw one card off a standard deck of 52 cards. If you draw a spade you get paid $12, if you draw a re

Mariulka [41]

Step-by-step explanation:

In a standard deck of 52 cards, there are 2 red aces, 2 red Queens, and 13 spades. That leaves 35 cards for everything else.

For the game to be fair, the cost must equal the expected value. The expected value is the sum of each outcome times its probability.

C = (12) (13/52) + (20) (2/52) + (38) (2/52) + (0) (35/52)

C = 68/13

C ≈ 5.2308

4 0

2 years ago

Which of the following can be a solution to the inequality below?<br> 2x > 6.<br> Pls send help

Citrus2011 [14]

Answer:

x>3

Step-by-step explanation:

you divide both sides by 2 then you get three. The sign remains the same.

3 0

3 years ago

How to solve <br> 12 x 3/4

tamaranim1 [39]

Answer:

Step-by-step explanation:

Write the fractions in fraction form 12/1 x 3/4

Multiply numerator x numerator and denominatior x denominato

You will get 36/4

36/4 = 9

5 0

3 years ago

For the figure, which of the following is true? I. m∠1+m∠2=m∠6+m∠5 II. m∠1+m∠3=m∠6+m∠4 III. m∠1+m∠3+m∠6=m∠2+m∠4+m∠5 A. I only B.

Alexxx [7]

Yea the answers 9!!!!!!

3 0

2 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

2 years ago

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