Ask question

Ask question

All categories

3 years ago

7

4≤n−4. a little help?

2 answers:

Dominik [7]3 years ago

7 0

Answer:

n ≥ 8

Step-by-step explanation:

We want to isolate n to solve the inequality. To do that, you add 4 to both sides, so 4 + 4 = 8 on the left and n - 4 + 4 = n on the right. That leaves you with 8 ≤ n, or n ≥ 8.

saveliy_v [14]3 years ago

5 0

Answer:

Just isolate the variable by performing inverse operations. Its like solving an equation but the sign is different.

Step-by-step explanation:

Well add 4 to both sides

8≤n

Thats basically it

You might be interested in

Task: Nonpermissible Values for Rational Expressions [30 points] Write a rational expression that has the nonpermissible values

igor_vitrenko [27]

Answer:

A rational expression that has the nonpermissible values $x = 0$ and $x = 17$ is $f(x) = \frac{4}{x\cdot (x-17)}$ .

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of $x$ , the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

$f(x) = \frac{p(x)}{q(x)}$ (1)

Then, the factorized form of $q(x)$ must be:

$q(x) = x\cdot (x-17)$ (2)

If we know that $p(x) = 4$ , then the rational expression is:

$f(x) = \frac{4}{x\cdot (x-17)}$ (3)

A rational expression that has the nonpermissible values $x = 0$ and $x = 17$ is $f(x) = \frac{4}{x\cdot (x-17)}$ .

8 0

3 years ago

4/3 (4•5)} = 203 <br><br> ? = 203

Marta_Voda [28]

Answer:

4/3 (4•5)} = 203

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: $(x-h)^2+(y-k)^2=r^2$

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

$(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36$

So, equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

5 0

3 years ago

Free 5 points ig here you go have a great day and weekend and happy Valentin's day 1+5=6 yay somebody please get them im getting

lesantik [10]

Answer:

thenk you for the points give me brainlist pleasee

5 0

3 years ago

Read 2 more answers

How do I figure this out

ddd [48]

I agree. There can't ever be 2 equal signs in A math problem

5 0

4 years ago