B is the correct answer.
multiply both top an bottom by √50, the denominator is -150, the numerator is 2√250 before simplifying.
Answer:
where are the answer choices
Step-by-step explanation:
Step-by-step explanation:
![2m - x \div x \\ \frac{x(2m \div x) - 1}{1}](https://tex.z-dn.net/?f=2m%20-%20x%20%5Cdiv%20x%20%5C%5C%20%5Cfrac%7Bx%282m%20%5Cdiv%20x%29%20-%201%7D%7B1%7D%20)
hope it helps
For two complex numbers
![z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)](https://tex.z-dn.net/?f=z_1%3Dre%5E%7Bi%5Ctheta%7D%3Dr%28%5Ccos%5Ctheta%2Bi%5Csin%5Ctheta%29)
and
![z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)](https://tex.z-dn.net/?f=z_2%3Dse%5E%7Bi%5Cvarphi%7D%3Ds%28%5Ccos%5Cvarphi%2Bi%5Csin%5Cvarphi%29)
, the product is
![z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))](https://tex.z-dn.net/?f=z_1z_2%3Drse%5E%7Bi%28%5Ctheta%2B%5Cvarphi%29%7D%3Drs%28%5Ccos%28%5Ctheta%2B%5Cvarphi%29%2Bi%5Csin%28%5Ctheta%2B%5Cvarphi%29%29)
That is, you multiply the moduli and add the arguments. You have
![z_1=7e^{i40^\circ}](https://tex.z-dn.net/?f=z_1%3D7e%5E%7Bi40%5E%5Ccirc%7D)
and
![z_2=6e^{i145^\circ}](https://tex.z-dn.net/?f=z_2%3D6e%5E%7Bi145%5E%5Ccirc%7D)
, so the product is
Answer:
I think its 2nd one
HOPE IT HELPS, BE SAFE! Brainiest if possible pls! :)