To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer: c
Step-by-step explanation:
The initial equation is:
Let's transform it for x:
... distract 5:
... divide both sides by 5:
Answer:
(-∞,4)
Step-by-step explanation:
the value is going down from the right until it reaches the vertex
SOH CAH TOA.
Sin = Opposite / Hypotenuse
Cos = Adjacent / Hypotenuse
Tan = Opposite / Adjacent
