419
<h2>
4=400</h2><h2>
1=100</h2><h2>
9=900</h2>
i think that's how you do that I've never done that before
Step-by-step explanation:
The “fun size” of a Snickers bar is supposed to weigh 20 grams. Because the penalty for selling Snickers candy bars that weigh less than 20 grams is so severe, the manufacturer calibrates the machine so that the mean weight is 20.2 grams. The quality control manager at the candy company is concerned that the candy produced does not weigh 20.2 grams. She obtains a random sample of 64 candy bars and weighs them. She finds that the mean weight of this sample is 20.05 grams with standard deviation 0.72. By answering the following questions, test the claim that the Snickers bars have a mean weight less than 20.2 grams at the level of α = 0.01.
1. Select from the following list all the requirements that are met in this problem scenario for this test: (circle your choice(s))
a. The population is approximately normal.
b. The population standard deviation is known.
c. The sample taken is a random sample.
d. The population standard deviation is unknown. e
. The degrees of freedom is 0.01.
f. The sample size is greater than 30.
2. Which of the following statements is correct?
a) Parameters describe sample characteristics.
b) Statistics describe population characteristics.
c) We use statistics to estimate the value of parameters.
d) We use parameters to estimate the value of statistics
Expert Answer
Answer:charlidamelio sucks at sing ✨robbery by juice wrld ✨ just saying and two exactly
Step-by-step explanation:
The expected value is $0.11.
The probability that the player will make the next free throw is 233/402. The probability that the next 3 are made will be (233/402)^3. To find the expected value of this, we multiply by the winnings we would have in this case, 166. So far we have:
((233/402)^3)(166)
The probability that the next 3 are not made is 1-((233/402)^3). Multiply this by the loss, -40, to get its expected value. This gets us to:
((233/402)^3)(166)-(1-((233/402)^3)).
This comes out to $0.11.
