For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
The solution of the quadratic equation is x = 0 or x = 6 ⇒ 4th answer
Step-by-step explanation:
The form of the quadratic equation is ax² + bx + c = 0, where
- a is the coefficient of x²
- b is the coefficient of x
- c is the numerical term
The quadratic equations has two roots, to find them factorize it into two factors and equate each factor by zero
∵ 3x = 0.5 x²
- Subtract 3x from both sides
∴ 0 = 0.5x² - 3x
- Multiply both sides by 2 to make the coefficient of x² integer
∴ 0 = x² - 6x
- Switch the two sides
∴ x² - 6x = 0
- Factorize it by taking x as a common factor
∴ x(x - 6) = 0
- Equate each factor by 0
∴ x = 0 → 1st root
∴ x - 6 = 0
- Add 6 to both sides
∴ x = 6 → 2nd root
∴ The roots of the equation are 0 or 6
The solution of the quadratic equation is x = 0 or x = 6
Learn more:
You can learn more about the quadratic equation in brainly.com/question/1357167
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Answer:
48 years
Step-by-step explanation:
See the photo. You can solve it 2 different ways, one being cross multiplication, and the other being simplifying.
If you cut the rectangle (the wall) diagonally, you get two congruent triangles. The measurements of the sides of one the triangles is 8, 15 and x. There is a pythagorean triples 8, 15, 17 so x has to be 17. if you dont know the triple you can do a^2 + b^2 = c^2 8^2 + 15^2 = c^2 c = 17
the diagonal of wall should be 17
the answer is d hoped i helped you
-jv