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Ronch [10]
3 years ago
11

If f(x) = 2x - 6 and g(x) = x, what is (g°7 (6)?

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer: B. -112 on edge :)

telo118 [61]3 years ago
6 0

Answer:

g(f(6)) = 6

Step-by-step explanation:

The two functions are:

f(x)  = 2x - 6

g(x) = x

$ f \circ g(x) = f(g(x)) $

i.e., g(x) becomes the input for f(x).

Here, we are asked to determine g(f(x)).

We will have: g(f(x)) = g(2x - 6)

Since, g(x) = x, g(2x - 6) = 2x - 6

When x = 6, g(f(6)) = 2(6) - 6

= 12 - 6 = 6

g(f(6)) = 6 is the answer.

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Write as a single power of 8.<br> 8 to the power of 8<br><br> ÷<br> 8 to the power of 2
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7 0
3 years ago
Brainliest
STALIN [3.7K]

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3 0
4 years ago
A chemist has 200 mL of a 10% sucrose solution. She adds x mL of a 40% sucrose solution. The percent concentration, y, of the fi
user100 [1]

Answer:

The chemist needs to add 400mL of 40% solution.

Step-by-step explanation:

The equation

y=\frac{0.1(200)+0.4x}{200+x} *100

gives the percent concentration y of the final mixture, when x mL of the 40% solution are added.

Now we are asked, how many milliliters x of the 40% solution should the chemist add to get final percent concentration y=30; this is just a matter of solving the equation

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and we solve it the following way:

30=\frac{0.1(200)+0.4x}{200+x} *100\\\\0.3 =\frac{0.1(200)+0.4x}{200+x}\\\\0.3(200+x)=0.1(200)+0.4x\\\\60+0.3x=20+0.4x\\\\40=0.1x\\\\x=\frac{40}{0.1} \\\\\boxed{x=400\:mL}

Thus, the chemist needs 400mL of 40% solution to get 30% concentration of the final mixture.

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4 years ago
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