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Goryan [66]
4 years ago
10

Brainliest

Mathematics
1 answer:
STALIN [3.7K]4 years ago
3 0

the line of best fit would be something like in the picture(but straighter)

you would get the equation of it by using y = mx+c

m = the change of y divided by the change of x on the line

c = when the line was on the y axis

put the values in y = mx + c and you have the equation

once you have that just replace x with 100 and rearrange it to equal y and you have the customers

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3x + 2y = 6 what is x and y
uysha [10]

Answer:

For 3x + 2y = 6 , the x-intercept is 2 and the y-intercept is 3.

4 0
3 years ago
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Find the limiting value using L hospital​
viktelen [127]

Answer:

  -1

Step-by-step explanation:

The expression evaluates to the indeterminate form -∞/∞, so L'Hopital's rule is appropriately applied. We assume this is the common log.

  d(log(x))/dx = 1/(x·ln(10))

  d(log(cot(x)))/dx = 1/(cot(x)·ln(10)·(-csc²(x)) = -1/(sin(x)·cos(x)·ln(10))

Then the ratio of these derivatives is ...

  lim = -sin(x)cos(x)·ln(10)/(x·ln(10)) = -sin(x)cos(x)/x

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At x=0, this has the indeterminate form 0/0, so L'Hopital's rule can be applied again.

  d(-sin(x)cos(x))/dx = -cos(2x)

  dx/dx = 1

so the limit is ...

  lim = -cos(2x)/1

  lim = -1 when evaluated at x=0.

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I find it useful to use a graphing calculator to give an estimate of the limit of an indeterminate form.

5 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST NO RANDOM ANSWERS
Ray Of Light [21]

Answer:

− 6 y  +  4 +  6 y  −  4 + 2

Step-by-step explanation:

3 0
3 years ago
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Find f(-2) for (x) = 3 . 2^x<br> O A. -36<br> O B. -12<br> O c.1/36<br><br> O D. 3/4
nydimaria [60]

\sf f(x) = 3  \ * \  2^x

insert x = -2

\sf f(-2) = 3  \ * \  2^{-2}

\sf f(-2) = 3  \ * \  \dfrac{1}{4}

\sf f(-2) = \dfrac{3}{4}

option D. 3/4 will be the correct answer.

6 0
2 years ago
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Rewrite in standard form of a circle<br> x^2-6x+y^2-4y-12=0​
cricket20 [7]

Answer: (x-3)^{2} + (y-2)^{2} = 5^{2}

Step-by-step explanation:

The standard form of equation of a circle is written in the form:

(x-a)^{2} + (y-b)^{2} = r^{2}

where a and b are the coordinates of the center and r is the radius.

All we need to do is to covert the given equation into this form, how do we do that?

We will achieve this by using the completing method of solving quadratic equation.

Firstly re - write the equation , that is

x^{2} - 6x + y^{2}-4y = 12

The next thing is to Complete the square for each of  x and y

How do we do this ?

i. multiply the coefficient of x and y by 1/2

ii. square the results

iii. Add the result to both sides of the equation , that is

x^{2} - 6x + 3^{2} - 4y + 2^{2} = 12 +3^{2}+2^{2}

The next thing is to write the Left hand side of the equation as a perfect square binomial and simplify the Right hand side. That is

(x-3)^{2} + (y-2)^{2} = 25 , that is

(x-3)^{2} + (y-2)^{2} = 5^{2}

Which is now in standard form of the equation of a circle.

6 0
3 years ago
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