6x²-5x-4=0
x=(-b+/√b²-4ac)/2a
D=b²-4ac=25+4*6*4=121, √D=√121=11
x=(5+/-11)/12
x1=-6/12=-1/2
x2=16/12=4/3
The answer is B. The values of y must only be positive because it is equal to

The other options states that the values of y could be negative which is why it is wrong.
I am not really sure but you could try working it out this way;
12/27, 24/54, 36/81, 48/108, 60/135, 72/162
<h3>Hello There!!</h3><h2 /><h3><u>Given</u></h3>

<h3><u>Solving </u><u>It</u></h3>
![3(x - 2) + 7x = \frac{1}{2} (6x - 2) \\ \\ \implies3x - 6 + 7x = ([\frac{1}{2} \times 6 \: x] - [\frac{1}{2} \times 2]) \\ \\ \implies10x - 6 = ([\frac{1}{ \cancel2} \times \cancel 6 \: x] - [\frac{1}{ \cancel2} \times \cancel2]) \\ \\ \implies 10x - 6 = 3x - 1 \\ \\ \fbox{Bringing (3x )to left side whereas( - 6 )in right side} \\ \\ \implies10x - 3x = - 1 + 6 \\ \\ \implies7x = 5 \\ \\ \therefore x = \frac{5}{7}](https://tex.z-dn.net/?f=3%28x%20-%202%29%20%2B%207x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%286x%20-%202%29%20%20%5C%5C%20%20%5C%5C%20%20%5Cimplies3x%20-%206%20%2B%207x%20%3D%20%20%28%5B%5Cfrac%7B1%7D%7B2%7D%20%20%20%5Ctimes%206%20%5C%3A%20x%5D%20-%20%20%5B%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%202%5D%29%20%5C%5C%20%5C%5C%20%20%20%5Cimplies10x%20-%206%20%20%3D%20%20%28%5B%5Cfrac%7B1%7D%7B%20%5Ccancel2%7D%20%20%20%5Ctimes%20%5Ccancel%206%20%5C%3A%20x%5D%20-%20%20%5B%5Cfrac%7B1%7D%7B%20%5Ccancel2%7D%20%20%5Ctimes%20%20%5Ccancel2%5D%29%20%5C%5C%20%20%5C%5C%20%20%5Cimplies%2010x%20-%206%20%3D%203x%20-%201%20%5C%5C%20%20%5C%5C%20%20%5Cfbox%7BBringing%20%283x%20%29to%20left%20side%20whereas%28%20%20-%206%20%29in%20right%20side%7D%20%5C%5C%20%20%5C%5C%20%20%5Cimplies10x%20-%203x%20%3D%20%20-%201%20%2B%206%20%5C%5C%20%20%5C%5C%20%20%5Cimplies7x%20%3D%205%20%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20x%20%3D%20%20%5Cfrac%7B5%7D%7B7%7D%20)
The Solution is = 

<h3>Hope This Helps</h3>