Answer:
Helium, Neon, Argon, Krypton, Xenon, Radon, and Oganesson
Explanation:
they have full outer shells
Answer:
The answer is
<h2>0.14 g</h2>
Explanation:
To find the mass of a substance given the density and volume we use the formula
<h3>mass = Density × volume</h3>
From the question
Density = 1.122 g/L
volume = 125 mL
We must convert the volume from mL to L
1000 mL = 1 L
125 mL = 0.125 L
volume = 0.125 L
Substitute the values into the above formula and solve for the mass
That's
mass = 1.122 × 0.125 = 0.14025
We have the final answer as
<h3>0.14 g</h3>
Hope this helps you
Answer:
Nitrogen emissions such as ammonia, nitrogen oxide and nitrous oxides contribute to particulate matter and acid rain. Nitrous oxide is a particularly potent greenhouse gas as it is over 300 times more effective at trapping heat in the atmosphere than carbon dioxide.
Explanation:
Pressure. We know this because of Boyle’s law, which states that the volume of gas and pressure are inversely proportional at a given temp.
<span>Converting from mass (grams) to moles: Divide your initial mass by the molar mass of the compound as determined by the periodic table.<span>Converting from moles to mass (grams): </span>Multiply your initial mole value by the molar mass of the compound as determined by the periodic table.<span>Converting from volume (liters) to moles: </span>Divide your initial volume by the molar volume constant, 22.4 L.<span>Converting from moles to volume (liters): </span>Multiply your mole value by the molar volume constant, 22.4L.<span>Converting from particles (atoms, molecules, or formula units) to moles: </span>Divide your particle value by Avogadro’s number, 6.02×1023. Remember to use parentheses on your calculator!<span>Converting from moles to particles (atoms, molecules, or formula units): </span>Multiply your mole value by Avogadro’s number, 6.02×1023.<span>Mole-to-mole conversions: </span>Use the coefficients from your balanced equation to determine your conversion factor. Be sure your units cancel out so you end up with the correct mole value.</span>