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Nostrana [21]
3 years ago
6

Sherman goes golfing every 6th day and brad goes golfing every 7th day.if sherman and brad both went golfing today, how many day

s until they will go golfing on the same day again?
Mathematics
1 answer:
Paraphin [41]3 years ago
6 0
In this item, we are basically to get the value of the least number that can be divided both by 6 and 7. In other words, we are to get the least common multiple or (LCM). This is obtained by multiplying the 2 numbers. Thus, after 42 days, they will go golfing the same day again. 
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Each of the following statements describes a quadrilateral. Which of the quadrilaterals are NOT parallelograms? Choose three.
Elina [12.6K]
1 st 2nd and 4th are NOT parallelograms.
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3 years ago
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The average distance from the sun to Venus is 67,237,910 miles. The average distance from the sun to earth is 92,955,807 miles
murzikaleks [220]
Find the difference, so subtract the two and you should get the answer from earth to Venus
3 0
3 years ago
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Write an equation in slope intercept form for a line that passed through the two points below (-4,7), (8,1)
vichka [17]
Y= -1/2x + 5
Good luck!!!!
7 0
3 years ago
3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k
Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt

Evaluate the integral to solve for y :

\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt

\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x

\displaystyle y = x^3+2x^2+kx - 2

Use the other known value, f(2) = 18, to solve for k :

18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}

Then the curve C has equation

\boxed{y = x^3 + 2x^2 + 2x - 2}

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2

The slope of the given tangent line y=x-2 is 1. Solve for a :

3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1

So, the point of contact between the tangent line and C is (-1, -3).

7 0
2 years ago
Drag and drop the answer into the box to identify each function as linear, exponential, or neither.
katrin2010 [14]
<span>​x​ 2 3 4
f(x) 5.5 7 8.5 </span>

The first function is linear. When you subtract 5.5 from 7, you get 1.5 and when you subtract 7 from 8.5 you also get 1.5. That's how we know it's a linear function because there's clearly pattern. HOWEVER, if you had 5.5, 7, and 9 that would not be a linear function. Why? Because when you take away 7 from 9 you get 2. In order for it to be a linear function you have to get the same exact number when you subtract. 

<span>x​ 0 3 6
f(x) 1 8 64</span> 

The second function is exponential because when you divide you get the exact same number. 8/1 = 8 and 64/8 = 8. So this is exponential. But if you had 72 instead of 64 it would not be an exponential function because there has to be a pattern. 

I hope this makes sense. Btw I had this question on my test too and this is correct. 
4 0
3 years ago
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